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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Which of the following compounds would undergo aldol condensation, which the Cannizzaro reaction and which neither? Write the structures of the expected products of aldol condensation

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प्रश्न

Which of the following compounds would undergo aldol condensation, which the Cannizzaro reaction and which neither? Write the structures of the expected products of aldol condensation and Cannizzaro reaction.

  1. Methanal
  2. 2-Methylpentanal
  3. Benzaldehyde
  4. Benzophenone
  5. Cyclohexanone
  6. 1-Phenylpropanone
  7. Phenylacetaldehyde
  8. Butan-1-ol
  9. 2, 2-Dimethylbutanal
रासायनिक समीकरण/संरचनाएँ
दीर्घउत्तर
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उत्तर

Aldehydes and ketones having at least one α-hydrogen undergo aldol condensation.

The compounds (ii) 2-Methylpentanal, (v) Cyclohexanone, (vi) 1-phenylpropanone, and (vii) Phenylacetaldehyde contain one or more α-hydrogen atoms. Therefore, these undergo aldol condensation.

Aldehydes having no α-hydrogen atoms undergo Cannizzaro reactions. The compounds (i) Methanal, (iii) Benzaldehyde, and (ix) 2, 2-dimethylbutanal do not have any α-hydrogen. Therefore, these undergo cannizzaro reactions.

Compound (iv) Benzophenone is a ketone having no α-hydrogen atom and compound (viii) Butan-1-ol is an alcohol. Hence, these compounds do not undergo either aldol condensation or cannizzaro reactions.

Aldol condensation:

(ii)

\[\begin{array}{cc}
\phantom{...................................................}\ce{CH3}\\
\phantom{................................................}|\\
\ce{2CH3CH2CH2 - CH - CHO ->[dil NaOH] CH3CH2CH2 - CH - CH - CH - CH2CH2CH3}\\
|\phantom{...................................}|\phantom{......}|\phantom{......}|\phantom{}\\
\phantom{......}\ce{\underset{2-Methylpentanal}{CH3}}\phantom{....................}\ce{\underset{3-Hydroxy-2,4-dimethyl-2-propylheptanal}{\phantom{..}CH3\phantom{...}OH\phantom{...}CHO}}
\end{array}\]

(v)

(vi)

(vii)

Cannizzaro reaction:

(i)
\[\begin{array}{cc}
\ce{H}\phantom{..............................}\ce{H}\phantom{.......}\ce{H}\phantom{......}\\
\backslash\phantom{..............................}|\phantom{.........}\backslash\phantom{....}\\
\ce{2\phantom{...}C = O + conc.KOH -> H - C - OH + C - OK}\\
/\phantom{..............................}|\phantom{.........}/\phantom{....}\\
\ce{\underset{Methanal}{H}}\phantom{..........................}\ce{\underset{Methanol}{H}}\phantom{.}\ce{\underset{methanoate}{\underset{Potassim}{H}}}\phantom{......}
\end{array}\]
(iii)

(ix)

\[\begin{array}{cc}
\phantom{.....}\ce{CH3}\phantom{............................}\ce{CH3}\phantom{........................}\ce{CH3}\phantom{...}\\
\phantom{}|\phantom{...............................}|\phantom{............................}|\phantom{.}\\
\ce{CH3CH2 - C - CHO ->[conc. NaOH] CH3CH2 - C - CH2 - OH + CH3CH2 - C - C - ONa}\\
\phantom{.....}|\phantom{...............................}|\phantom{............................}|\phantom{....}||\phantom{}\\
\phantom{.........}\ce{\underset{2, 2-Dimethylbutanal}{CH3}}\phantom{...............}\ce{\underset{2, 2-Dimethylbutan-1-ol}{CH3}}\phantom{..........}\ce{\underset{Sodium 2, 2-dimethylbutanoate}{CH3\phantom{.}O}}\phantom{.}
\end{array}\]

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अध्याय 8: Aldehydes, Ketones and Carboxylic Acids - Exercises [पृष्ठ २५६]

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एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
अध्याय 8 Aldehydes, Ketones and Carboxylic Acids
Exercises | Q 8.7 | पृष्ठ २५६

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\[\ce{CH3-CH2-CHO ->[dil][alkali] Product}\]

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When acetaldehyde is treated with dilute NaOH, the following reaction is observed.

\[\begin{array}{cc}
\ce{2CH3 - CHO ->[dil.NaOH] CH3 - CH - CH2 - CHO}\\
\phantom{...............}|\\
\phantom{.................}\ce{OH}
\end{array}\]

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