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प्रश्न
Explain aldol condensation reaction in detail.
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उत्तर
- Aldehydes containing at least one α–hydrogen atom undergo a reaction in presence of dilute alkali (dilute NaOH, KOH, or Na2CO3) as the catalyst to form β-hydroxy aldehydes (aldol). This reaction is known as the aldol reaction.
- Formation of aldol is an addition reaction.
- Aldol formed from aldehyde having α-hydrogens undergoes subsequent elimination of water molecule on warming. This gives rise to α,β-unsaturated aldehyde.
- The overall reaction is called aldol condensation. It is a nucleophilic addition-elimination reaction.
- The reaction can be given as,
\[\begin{array}{cc}
\ce{\underset{\text{Aldehyde}}{2R - CH2 - CHO} ->[aq.NaOH] R - CH2 - CH - CHR - CHO}\\
\phantom{.......................}|\\
\phantom{..........................}\ce{\underset{\text{Aldol}}{OH}}
\end{array}\]
\[\begin{array}{cc}
\ce{R - CH2 - CH - CHR - CHO ->[-H2O][warm] \underset{\text{α,β-Unsaturated aldehyde}}{R - CH = CR - CHO}}\\
|\phantom{.......................................}\\
\ce{\underset{Aldol}{OH}}\phantom{.....................................}
\end{array}\]
e.g.
- Ketones containing at least two α-hydrogen also undergo aldol condensation reaction and give an α,β-unsaturated ketone.
e.g.
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\[\begin{array}{cc}
\ce{C6H5CHO}\phantom{............}\\
\phantom{........}\ce{+\phantom{......}\ce{->[dil.NaOH][\Delta]}}\phantom{...}\\
\ce{CH3CH2CHO}\phantom{............}
\end{array}\]
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(i) \[\ce{CH3 - CHO}\]
(ii) 
(iii) \[\begin{array}{cc}
\phantom{}\ce{O}\\
\phantom{}||\\
\ce{CH3 - C - CH3}
\end{array}\]
(iv) \[\begin{array}{cc}
\phantom{}\ce{CH3}\\
|\phantom{...}\\
\ce{CH3 - C - CHO}\phantom{..}\\
|\phantom{...}\\
\phantom{}\ce{CH3}\\
\end{array}\]
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