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What product will be formed on reaction of propanal with 2-methylpropanal in the presence of NaOH? What products will be formed? Write the name of the reaction also.

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प्रश्न

What product will be formed on reaction of propanal with 2-methylpropanal in the presence of \[\ce{NaOH}\]? What products will be formed? Write the name of the reaction also.

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उत्तर

It is cross Aldol condensation

\[\begin{array}{cc}
\phantom{}\ce{CH3}\phantom{.................}\ce{OH}\phantom{...............}\ce{CH3}\phantom{..........}\ce{CH3}\phantom{............}\ce{CH3}\phantom{.}\ce{OH}\phantom{...}\ce{CH3}\phantom{....}\ce{H3C}\phantom{...}\\
\phantom{}|\phantom{....................}|\phantom{..................}|\phantom{.............}|\phantom{................}|\phantom{....}|\phantom{......}|\phantom{...........}\backslash\phantom{.}\\
\phantom{}\ce{CH3CH2CHO + CH3CHCH3 -> CH3CH2CH - C - CHO + CH2 - CH = C - CHO + CH3C - CH - C - CHO + CH - CH = C - CHO}\phantom{}\\
\phantom{................................................................}|\phantom{..........................}|\phantom{...........}/\phantom{.............}|\phantom{}\\
\phantom{...................................................................}\ce{CH3}\phantom{.......................}\ce{CH3}\phantom{...}\ce{H3C}\phantom{...............}\ce{CH3}\phantom{}
\end{array}\]

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अध्याय 12: Aldehydes, Ketones and Carboxylic Acids - Multiple Choice Questions (Type - I) [पृष्ठ १७३]

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एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 12
अध्याय 12 Aldehydes, Ketones and Carboxylic Acids
Multiple Choice Questions (Type - I) | Q 28 | पृष्ठ १७३

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\[\begin{array}{cc}
\ce{CH3}\phantom{.................}\\
|\phantom{....................}\\
\phantom{}\ce{2CH3 - C = O ->[Ba(OH)2] A ->[Δ] B + H2O}
\end{array}\]


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When acetaldehyde is treated with dilute NaOH, the following reaction is observed.

\[\begin{array}{cc}
\ce{2CH3 - CHO ->[dil.NaOH] CH3 - CH - CH2 - CHO}\\
\phantom{...............}|\\
\phantom{.................}\ce{OH}
\end{array}\]

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Which one of the following undergoes reaction with 50% sodiumhydroxide solution to give the corresponding alcohol and acid:


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