हिंदी

Why is the α-hydrogens of aldehydes and ketones are acidic in nature?

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प्रश्न

Why is the α-hydrogens of aldehydes and ketones are acidic in nature?

Account for the following:

The alpha (α)-hydrogens of aldehydes and ketones are acidic in nature.

रासायनिक समीकरण/संरचनाएँ
लघु उत्तरीय
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उत्तर

Because of the strong electron-withdrawing nature of the carbonyl groups and the resonance stabilisation of the conjugate base, aldehydes and ketones are acidic in nature.

\[\begin{array}{cc}
\ce{R}\phantom{..........}\\
\backslash\phantom{........}\\
\ce{C = O}\\
/\phantom{........}\\
\ce{H}\phantom{..........}\\
\end{array}\]
\[\begin{array}{cc}
\ce{R}\phantom{..........}\\
\backslash\phantom{........}\\
\ce{C = O}\\
/\phantom{........}\\
\ce{R}\phantom{..........}\\
\end{array}\]
Aldehyde Ketone
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2022-2023 (March) Delhi Set 1

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संबंधित प्रश्न

Which of the following compounds do not undergo aldol condensation?

(i) \[\ce{CH3 - CHO}\]

(ii)  

(iii)  \[\begin{array}{cc}
\phantom{}\ce{O}\\
\phantom{}||\\
\ce{CH3 - C - CH3}
\end{array}\]

(iv) \[\begin{array}{cc}
\phantom{}\ce{CH3}\\
|\phantom{...}\\
\ce{CH3 - C - CHO}\phantom{..}\\
|\phantom{...}\\
\phantom{}\ce{CH3}\\
\end{array}\]


Assertion: The α-hydrogen atom in carbonyl compounds is less acidic.

Reason: The anion formed after the loss of α-hydrogen atom is resonance stabilised.


Assertion: Aromatic aldehydes and formaldehyde undergo Cannizaro reaction.

Reason: Aromatic aldehydes are almost as reactive as formaldehyde.


Which of the following gives aldol con~ensation reaction?


Identify A and B from the following reaction:

\[\begin{array}{cc}
\ce{CH3}\phantom{.................}\\
|\phantom{....................}\\
\phantom{}\ce{2CH3 - C = O ->[Ba(OH)2] A ->[Δ] B + H2O}
\end{array}\]


Convert the following:

Acetaldehyde to But-2-enal


The major product of the following reaction is:


Which of the following does not give aldol condensation reaction?


Identify A and B:


When acetaldehyde is treated with dilute NaOH, the following reaction is observed.

\[\begin{array}{cc}
\ce{2CH3 - CHO ->[dil.NaOH] CH3 - CH - CH2 - CHO}\\
\phantom{...............}|\\
\phantom{.................}\ce{OH}
\end{array}\]

  1. What are the functional groups in the product?
  2. Can another product be formed during the same reaction? (Deduce the answer by doing atomic audit of reactant and product).
  3. Is this an addition reaction or condensation reaction?

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