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प्रश्न
What product will be formed on reaction of propanal with 2-methylpropanal in the presence of \[\ce{NaOH}\]? What products will be formed? Write the name of the reaction also.
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उत्तर
It is cross Aldol condensation
\[\begin{array}{cc}
\phantom{}\ce{CH3}\phantom{.................}\ce{OH}\phantom{...............}\ce{CH3}\phantom{..........}\ce{CH3}\phantom{............}\ce{CH3}\phantom{.}\ce{OH}\phantom{...}\ce{CH3}\phantom{....}\ce{H3C}\phantom{...}\\
\phantom{}|\phantom{....................}|\phantom{..................}|\phantom{.............}|\phantom{................}|\phantom{....}|\phantom{......}|\phantom{...........}\backslash\phantom{.}\\
\phantom{}\ce{CH3CH2CHO + CH3CHCH3 -> CH3CH2CH - C - CHO + CH2 - CH = C - CHO + CH3C - CH - C - CHO + CH - CH = C - CHO}\phantom{}\\
\phantom{................................................................}|\phantom{..........................}|\phantom{...........}/\phantom{.............}|\phantom{}\\
\phantom{...................................................................}\ce{CH3}\phantom{.......................}\ce{CH3}\phantom{...}\ce{H3C}\phantom{...............}\ce{CH3}\phantom{}
\end{array}\]
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संबंधित प्रश्न
Write the products formed when CH3CHO reacts with the following reagents: CH3CHO in the presence of dilute NaOH
How will you convert ethanal into the following compound?
Butane-1, 3-diol
How will you convert ethanal into the following compound?
But-2-enal
Write structural formulas and names of four possible aldol condensation products from propanal and butanal. In each case, indicate which aldehyde acts as nucleophile and which as electrophile.
How will you bring about the following conversion in not more than two steps?
Ethanol to 3-Hydroxybutanal
How will you bring about the following conversion in not more than two steps?
Benzaldehyde to 3-Phenylpropan-1-ol
Describe the following:
Cross aldol condensation
Complete the synthesis by giving missing starting material, reagent or product.
\[\begin{array}{cc}
\ce{C6H5CHO}\phantom{............}\\
\phantom{........}\ce{+\phantom{......}\ce{->[dil.NaOH][\Delta]}}\phantom{...}\\
\ce{CH3CH2CHO}\phantom{............}
\end{array}\]
Why is alpha (α) hydrogen of carbonyl compounds acidic in nature?
Write a chemical equation for the following reaction:
Propanone is treated with dilute Ba( OH)2.
Which product is formed when the compound 
is treated with concentrated aqueous \[\ce{KOH}\] solution?
Which of the following compounds do not undergo aldol condensation?
(i) \[\ce{CH3 - CHO}\]
(ii) 
(iii) \[\begin{array}{cc}
\phantom{}\ce{O}\\
\phantom{}||\\
\ce{CH3 - C - CH3}
\end{array}\]
(iv) \[\begin{array}{cc}
\phantom{}\ce{CH3}\\
|\phantom{...}\\
\ce{CH3 - C - CHO}\phantom{..}\\
|\phantom{...}\\
\phantom{}\ce{CH3}\\
\end{array}\]
Assertion: The α-hydrogen atom in carbonyl compounds is less acidic.
Reason: The anion formed after the loss of α-hydrogen atom is resonance stabilised.
Identify A and B from the following reaction:
\[\begin{array}{cc}
\ce{CH3}\phantom{.................}\\
|\phantom{....................}\\
\phantom{}\ce{2CH3 - C = O ->[Ba(OH)2] A ->[Δ] B + H2O}
\end{array}\]
Predict the reagent for carrying out the following transformations:
Ethanal to 3-hydroxy butanal
\[\ce{CH3-CH2-CHO ->[dil][alkali] Product}\]
The product in the above reaction is:
Which of the following does not give aldol condensation reaction?
Which of the following compounds will undergo self-condensation in the presence of dilute NaOH solution?
