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प्रश्न
Which product is formed when the compound
is treated with concentrated aqueous \[\ce{KOH}\] solution?
पर्याय
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उत्तर

Explanation:
Benzaldehyde is having no a hydrogen. So, on reaction with aqueous KOH solution, it undergoes Cannizzaro’s reaction. One molecule of aldehyde is reduced and other is

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संबंधित प्रश्न
Which of the following compounds would undergo aldol condensation, which the Cannizzaro reaction and which neither? Write the structures of the expected products of aldol condensation and Cannizzaro reaction.
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- Benzophenone
- Cyclohexanone
- 1-Phenylpropanone
- Phenylacetaldehyde
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- 2, 2-Dimethylbutanal
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(i) Benzaldehyde into benzyl alcohol
(ii) Cyclohexanone into cyclohexane
(iii) Benzoyl chloride into benzaldehyde
(iv) Benzophenone into diphenyl methane
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\[\ce{CH3-CH2-CHO ->[dil][alkali] Product}\]
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Reason (R): α, β-unsaturated carbonyl compounds are stabilised due to conjugation.

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When acetaldehyde is treated with dilute NaOH, the following reaction is observed.
\[\begin{array}{cc}
\ce{2CH3 - CHO ->[dil.NaOH] CH3 - CH - CH2 - CHO}\\
\phantom{...............}|\\
\phantom{.................}\ce{OH}
\end{array}\]
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- Is this an addition reaction or condensation reaction?
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