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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Assertion: The α-hydrogen atom in carbonyl compounds is less acidic. Reason: The anion formed after the loss of α-hydrogen atom is resonance stabilised.

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प्रश्न

Assertion: The α-hydrogen atom in carbonyl compounds is less acidic.

Reason: The anion formed after the loss of α-hydrogen atom is resonance stabilised.

पर्याय

  • Assertion and reason both are correct and reason is correct explanation of assertion.

  • Assertion and reason both are wrong statements.

  • Assertion is correct statement but reason is wrong statement.

  • Assertion is wrong statement but reason is correct statement.

  • Assertion and reason both are correct statements but reasson is not correct explanation of assertion.

MCQ
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उत्तर

Assertion is wrong statement but reason is correct statement.

Explanation:

Because of the presence of electron-withdrawing carbonyl group, the alpha hydrogen atom in carbonyl compounds is acidic. In nature, hydrogen is very acidic.

Because the cation is released in the form of \[\ce{H-}\], the anion created after the loss of the -hydrogen atom is resonance stabilised. 

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पाठ 12: Aldehydes, Ketones and Carboxylic Acids - Multiple Choice Questions (Type - I) [पृष्ठ १७६]

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एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 12
पाठ 12 Aldehydes, Ketones and Carboxylic Acids
Multiple Choice Questions (Type - I) | Q 44 | पृष्ठ १७६

संबंधित प्रश्‍न

What is meant by the following term? Give an example of the reaction in the following case.

Aldol


How will you convert ethanal into the following compound?

Butane-1, 3-diol


How will you convert ethanal into the following compound?

But-2-enal


How will you bring about the following conversion in not more than two steps?

Ethanol to 3-Hydroxybutanal


How will you bring about the following conversion in not more than two steps?

Benzaldehyde to 3-Phenylpropan-1-ol


Describe the following:

Cross aldol condensation


Complete the synthesis by giving missing starting material, reagent or product.

\[\begin{array}{cc}
\ce{C6H5CHO}\phantom{............}\\
\phantom{........}\ce{+\phantom{......}\ce{->[dil.NaOH][\Delta]}}\phantom{...}\\
\ce{CH3CH2CHO}\phantom{............}
\end{array}\]


Explain aldol condensation reaction in detail.


Cannizaro’s reaction is not given by ______.


Which product is formed when the compound  is treated with concentrated aqueous \[\ce{KOH}\] solution?


Compounds A and C in the following reaction are:

\[\ce{CH3CHO ->[(i) CH3MgBr][(ii) H2O] (A) ->[H2SO4, Δ] (B) ->[Hydroboration oxidation] (C)}\]


Why is there a large difference in the boiling points of butanal and butan-1-ol?


Identify A and B from the following reaction:

\[\begin{array}{cc}
\ce{CH3}\phantom{.................}\\
|\phantom{....................}\\
\phantom{}\ce{2CH3 - C = O ->[Ba(OH)2] A ->[Δ] B + H2O}
\end{array}\]


Convert the following:

Acetaldehyde to But-2-enal


Predict the reagent for carrying out the following transformations:

Ethanal to 3-hydroxy butanal


Explain Aldol condensation of ethanal.


Assertion (A): The final product in Aldol condensation is always α, β-unsaturated carbonyl compound.

Reason (R): α, β-unsaturated carbonyl compounds are stabilised due to conjugation.


When acetaldehyde is treated with dilute NaOH, the following reaction is observed.

\[\begin{array}{cc}
\ce{2CH3 - CHO ->[dil.NaOH] CH3 - CH - CH2 - CHO}\\
\phantom{...............}|\\
\phantom{.................}\ce{OH}
\end{array}\]

  1. What are the functional groups in the product?
  2. Can another product be formed during the same reaction? (Deduce the answer by doing atomic audit of reactant and product).
  3. Is this an addition reaction or condensation reaction?

Which one of the following undergoes reaction with 50% sodiumhydroxide solution to give the corresponding alcohol and acid:


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