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Question
What product will be formed on reaction of propanal with 2-methylpropanal in the presence of \[\ce{NaOH}\]? What products will be formed? Write the name of the reaction also.
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Solution
It is cross Aldol condensation
\[\begin{array}{cc}
\phantom{}\ce{CH3}\phantom{.................}\ce{OH}\phantom{...............}\ce{CH3}\phantom{..........}\ce{CH3}\phantom{............}\ce{CH3}\phantom{.}\ce{OH}\phantom{...}\ce{CH3}\phantom{....}\ce{H3C}\phantom{...}\\
\phantom{}|\phantom{....................}|\phantom{..................}|\phantom{.............}|\phantom{................}|\phantom{....}|\phantom{......}|\phantom{...........}\backslash\phantom{.}\\
\phantom{}\ce{CH3CH2CHO + CH3CHCH3 -> CH3CH2CH - C - CHO + CH2 - CH = C - CHO + CH3C - CH - C - CHO + CH - CH = C - CHO}\phantom{}\\
\phantom{................................................................}|\phantom{..........................}|\phantom{...........}/\phantom{.............}|\phantom{}\\
\phantom{...................................................................}\ce{CH3}\phantom{.......................}\ce{CH3}\phantom{...}\ce{H3C}\phantom{...............}\ce{CH3}\phantom{}
\end{array}\]
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\[\begin{array}{cc}
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\[\begin{array}{cc}
\ce{CH3}\phantom{.................}\\
|\phantom{....................}\\
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