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प्रश्न
Arrange the following in decreasing order of their acidic strength and give reason for your answer.
\[\ce{CH3CH2OH, CH3COOH, ClCH2COOH, FCH2COOH, C6H5CH2COOH}\]
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उत्तर
The order is
\[\ce{ClCH2COOH > FCH2COOH > C6H5CH2COOH > CH3COOH > CH3CH2OH }\]
When compared to other alcohols \[\ce{CH3CH2OH}\] is the least acidic. Because of the halogen, \[\ce{FCH2COOH}\] is quite acidic. It is either an electron-donating group or an electron receiving group in acidic strength. Acidic strength increases as the number of electron withdrawing groups increases. The acidic strength of electron-donating groups diminishes.
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संबंधित प्रश्न
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\[\begin{array}{cc}
\phantom{.................}\ce{Br}\phantom{....}\ce{CH3}\phantom{.........}\ce{O}\phantom{...}\\
\phantom{................}|\phantom{......}|\phantom{............}||\phantom{..}\\
\ce{CH3 - CH2 - CH2CH - CH - CH2 - C - H}
\end{array}\]
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The correct IUPAC name for the given molecule should be
\[\begin{array}{cc}
\ce{H3C - \overset{H}{C} - \overset{H2}{C} - \overset{H}{C} - OH}\\
\phantom{.}|\phantom{.........}|\phantom{}\\
\phantom{...}\ce{CH3}\phantom{......}\ce{CH3}\phantom{}
\end{array}\]
is
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