मराठी

Show that the function f : R → R given by f(x) = x3 is injective. - Mathematics

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प्रश्न

Show that the function f : R → R given by f(x) = x3 is injective.

बेरीज
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उत्तर १

f : R → R is given as f(x) = x3.

Suppose f(x) = f(y), where x, y ∈ R.

⇒ x3 = y... (1)

Now, we need to show that x = y.

Suppose x ≠ y; their cubes will also not be equal.

⇒ x3 ≠ y3

However, this will be a contradiction to (1).

∴ x = y

Hence, f is injective.

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उत्तर २

Let x1, x2 ∈ R be such that

f(x1) = f(x2)

⇒ `x_1^3 = x_2^3`

⇒ x1 = x2

∴ f is one-one.

Hence, f(x) = x3 is injective.

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पाठ 1: Relations and Functions - Exercise 1.5 [पृष्ठ २९]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 1 Relations and Functions
Exercise 1.5 | Q 5 | पृष्ठ २९

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