मराठी

Let F = {(1, −1), (4, −2), (9, −3), (16, 4)} and G = {(−1, −2), (−2, −4), (−3, −6), (4, 8)}. Show that Gof is Defined While Fog is Not Defined. Also, Find Gof.

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प्रश्न

Let f = {(1, −1), (4, −2), (9, −3), (16, 4)} and g = {(−1, −2), (−2, −4), (−3, −6), (4, 8)}. Show that gof is defined while fog is not defined. Also, find gof.

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उत्तर

f = {(1, −1), (4, −2), (9, −3), (16, 4)} and g = {(−1, −2), (−2, −4), (−3, −6), (4, 8)}
: {1, 4, 9, 16} → {-1, -2, -3, 4} and g : {-1, -2, -3, 4} → {-2, -4, -6, 8}

Co-domain of f = domain of g
So, gof exists and gof : {1, 4, 9, 16} → {-2, -4, -6, 8}

(gof) (1g (f (1)g (12

(gof) (4g (f (4))=g (24

(gof) (9g (f (9)g  (36

(gof) (16=g (f (16)=g (48

So, go(1, 2), (4, 4), (9, 6), (16, 8}

But the co-domain of g is not same as the domain of f.
So, fog does not exist.

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पाठ 2: Functions - Exercise 2.2 [पृष्ठ ४६]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
पाठ 2 Functions
Exercise 2.2 | Q 3 | पृष्ठ ४६

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