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Classify the following function as injection, surjection or bijection : f : Q − {3} → Q, defined by f(x)=2x+3x-3 - Mathematics

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प्रश्न

Classify the following function as injection, surjection or bijection :

f : Q − {3} → Q, defined by `f (x) = (2x +3)/(x-3)`

बेरीज
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उत्तर

Injective Test:

x1 and x2 be any tow elements in the domain (Q - {3}), such that f(x1) = f(x2)

`(2x_1 + 3)/(x_1 - 3) = (2x_2 + 3)/(x_2 - 3)`

⇒ `(2x_1 + 3)(x_2 - 3) = (2x_2 + 3)(x_1 - 3)`

⇒`2x_1x_2 - 6x_1 + 3x_2 - 9 = 2x_1x_2 - 6x_2 + 3x_1 - 9`

⇒ `9x_1 = 9x_2`

⇒ `x_1 = x_2`

f is an injection.

Surjective test:

Let y be any elements in the co-domain (Q - {3}), such that f(x) = y for some elements ξnQ (Domain)

f(x) = y

`(2x + 3)/(x - 3) = y`

⇒ `2x + 3 = xy - 3y`

⇒ `2x - xy = -3y - 3`

⇒ `x(2 - y) = -3(y + 1)`

`x = (3(y + 1))/(y - 1)` Which is not defined at y = 2 

So, f is not a surjection.

Bijection test:

Here, f is an injective but not surjective, then it is not bijective.

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पाठ 2: Functions - Exercise 2.1 [पृष्ठ ३१]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 2 Functions
Exercise 2.1 | Q 5.12 | पृष्ठ ३१

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