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A Plate Current of 10 Ma is Obtained When 60 Volts Are Applied Across a Diode Tube.

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प्रश्न

A plate current of 10 mA is obtained when 60 volts are applied across a diode tube. Assuming the Langmuir-Child relation \[i_p  \infty  V_p^{3/2}\] to hold, find the dynamic resistance rp in this operating condition.

योग
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उत्तर

According to Lamgmuir-Child Law,
the relation between plate current (ip) and the plate voltage (Vp) is given by

\[i_p  = C {V_p}^{3/2}  ............(1)\]

Differentiating equation (1) with respect Vp, we get:-

\[\frac{d i_p}{d V_p} = \frac{3}{2}C {V_p}^{1/2} ............(2)\]

Dividing (2) and (1), we get:-

\[\frac{1}{i_p}\frac{d i_p}{d v_p} = \frac{3/2C {V_p}^{1/2}}{C {V_p}^{3/2}}\]

\[ \Rightarrow \frac{1}{i_p} . \frac{d i_p}{d v_p} = \frac{3}{2 V_p}\]

The dynamic resistance is given by:-

\[\frac{d v_p}{d i_p} = \frac{2 V_p}{3 i_p}\]

\[ r_p  = \frac{2 V_p}{3 i_p}\]

\[ r_p  = \frac{2 \times 60}{3 \times 10 \times {10}^{- 3}}\]

\[ r_p  = 4 \times  {10}^3  = 4  k\Omega\]

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अध्याय 41: Electric Current through Gases - Exercises [पृष्ठ ३५३]

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एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
अध्याय 41 Electric Current through Gases
Exercises | Q 10 | पृष्ठ ३५३

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