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(English Medium) ICSE Class 9 - CISCE Question Bank Solutions

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State Newton's second law of motion. Under what condition does it take the form F = ma?

[3] Laws of Motion
Chapter: [3] Laws of Motion
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How can Newton's first law of motion be obtained from the second law of motion?

[3] Laws of Motion
Chapter: [3] Laws of Motion
Concept: undefined >> undefined

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Use Newton's second law of motion to explain the following instance : 

A cricketer pulls his hands back while catching a fast moving cricket ball .

[3] Laws of Motion
Chapter: [3] Laws of Motion
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Use Newton's second law of motion to explain the following instance :
An athlete prefers to land on sand instead of hard floor while taking a high jump .

[3] Laws of Motion
Chapter: [3] Laws of Motion
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The correct form of Newton's second law is : 

[3] Laws of Motion
Chapter: [3] Laws of Motion
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The unit of linear momentum is :

[3] Laws of Motion
Chapter: [3] Laws of Motion
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The linear momentum of a body of mass m moving with velocity v is  : 

[3] Laws of Motion
Chapter: [3] Laws of Motion
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A body of mass 5 kg is moving with velocity 2 m s-1. Calculate its linear momentum.

[3] Laws of Motion
Chapter: [3] Laws of Motion
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The linear momentum of a ball of mass 50 g is 0.5 kg m s-1. Find its velocity.

[3] Laws of Motion
Chapter: [3] Laws of Motion
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Calculate the magnitude of force which when applied on a body of mass 0.5 kg produces an acceleration of 5 m s-2.

[3] Laws of Motion
Chapter: [3] Laws of Motion
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A force of 10 N acts on a body of mass 2 kg for 3 s, initially at rest. Calculate : The velocity acquired by the body

[3] Laws of Motion
Chapter: [3] Laws of Motion
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A force of 10 N acts on a body of mass 2 kg for 3 s, initially at rest. Calculate : Change in momentum of the body.

[3] Laws of Motion
Chapter: [3] Laws of Motion
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A force acts for 10 s on a stationary body of mass 100 kg, after which the force ceases to act. The body moves through a distance of 100 m in the next 5 s. Calculate: The velocity acquired by the body.

[3] Laws of Motion
Chapter: [3] Laws of Motion
Concept: undefined >> undefined

A force acts for 10 s on a stationary body of mass 100 kg, after which the force ceases to act. The body moves through a distance of 100 m in the next 5 s. Calculate : The magnitude of the force

[3] Laws of Motion
Chapter: [3] Laws of Motion
Concept: undefined >> undefined

A car is moving with a uniform velocity 30 ms-1. It is stopped in 2 s by applying a force of 1500 N through its brakes. Calculate the following values : The change in momentum of car.

[3] Laws of Motion
Chapter: [3] Laws of Motion
Concept: undefined >> undefined

A bullet of mass 50 g moving with an initial velocity 100 m s-1 strikes a wooden block and comes to rest after penetrating a distance 2 cm in it. Calculate: (i) Initial momentum of the bullet, (ii) Final momentum of the bullet, (iii) Retardation caused by the wooden block and (iv) Resistive force exerted by the wooden block.

[3] Laws of Motion
Chapter: [3] Laws of Motion
Concept: undefined >> undefined

State the magnitude and direction of the force of gravity acting on the body of mass 5 kg. Take g = 9.8 m s-2.

[3] Laws of Motion
Chapter: [3] Laws of Motion
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A ball is thrown vertically upwards. It returns 6 s later. Calculate the greatest height reached by the ball. (Take g = 10 m s−2)

[3] Laws of Motion
Chapter: [3] Laws of Motion
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A pebble is thrown vertically upwards with a speed of 20 m s-1. How high will it be after 2 s? (Take g = 10 m s-2)

[3] Laws of Motion
Chapter: [3] Laws of Motion
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How long will a stone take to fall to the ground from the top of a building 80 m high 

[3] Laws of Motion
Chapter: [3] Laws of Motion
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