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Using Binomial Theorem, evaluate of the following:(102)5

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Question

Using Binomial Theorem, evaluate of the following:
(102)5

Sum
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Solution

102 can be expressed as the sum or difference of two numbers whose powers are easier to calculate and then, Binomial Theorem can be applied.

It can be written that, 102 = 100 + 2

`(102)^5  =  (100 + 2)^5  = (100)^5  +  ^5C_1 (100)^4  xx 2  +  ^5C_2 (100)^3 2^2  + ^5C_3(100)^2  xx  2^3  +  ^5C_4(100)  xx  2^4  +  2^5`

= 5C0 (100)5 + 5C1 (100)4 (2) + 5C2 (100)3 (2)2 + 5C3 (100)2 (2)3 + 5C4 (100) (2)4 + 5C5 (2)5

= (100)5 + 5 (100)4 (2) + 10 (100)3 (2)2 + 10 (100)2 (2)3 + 5 (100) (2)4 + (2)5

= 10000000000 + 5 x 100000000 x 2 + 10 x 1000000 x 4 + 10 x 10000 x 8+5 x 100 x 16 + 32

= 10000000000 + 1000000000 + 40000000 + 800000 + 8000 + 32

= 11040808032

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Chapter 7: Binomial Theorem - EXERCISE 7.1 [Page 133]

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NCERT Mathematics [English] Class 11
Chapter 7 Binomial Theorem
EXERCISE 7.1 | Q 7. | Page 133

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