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Given the integers r > 1, n > 2, and coefficients of (3r)th and (r + 2)nd terms in the binomial expansion of (1 + x)2n are equal, then ______. - Mathematics

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Question

Given the integers r > 1, n > 2, and coefficients of (3r)th and (r + 2)nd terms in the binomial expansion of (1 + x)2n are equal, then ______.

Options

  • n = 2r

  • n = 3r

  • n = 2r + 1

  • None of these

MCQ
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Solution

Given the integers r > 1, n > 2, and coefficients of (3r)th and (r + 2)nd terms in the binomial expansion of (1 + x)2n are equal, then n = 2r.

Explanation:

Given that r > 1 and n > 2

Then `"T"_(3r) = "T"_(3r - 1 + 1)`

= `""^(2n)"C"_(3r - 1) * x^(3r - 1)`

And `"T_(r + 2) = "T"_(r + 1 + 1)`

= `""^(2n)"C"_(r + 1) x^(r + 1)`

We have `""^(2n)"C"_(3r - 1) = ""^(2n)"C"_(r + 1)`

⇒ 3r – 1 + r + 1 = 2n   `....[because ""^n"C"_p = ""^n"C"_q ⇒ n = p + q]`

⇒ 4r = 2n

n = 2r

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Chapter 8: Binomial Theorem - Exercise [Page 144]

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NCERT Exemplar Mathematics [English] Class 11
Chapter 8 Binomial Theorem
Exercise | Q 19 | Page 144

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