हिंदी

Given the integers r > 1, n > 2, and coefficients of (3r)th and (r + 2)nd terms in the binomial expansion of (1 + x)2n are equal, then ______.

Advertisements
Advertisements

प्रश्न

Given the integers r > 1, n > 2, and coefficients of (3r)th and (r + 2)nd terms in the binomial expansion of (1 + x)2n are equal, then ______.

विकल्प

  • n = 2r

  • n = 3r

  • n = 2r + 1

  • None of these

MCQ
रिक्त स्थान भरें
Advertisements

उत्तर

Given the integers r > 1, n > 2, and coefficients of (3r)th and (r + 2)nd terms in the binomial expansion of (1 + x)2n are equal, then n = 2r.

Explanation:

Given that r > 1 and n > 2

Then `"T"_(3r) = "T"_(3r - 1 + 1)`

= `""^(2n)"C"_(3r - 1) * x^(3r - 1)`

And `"T_(r + 2) = "T"_(r + 1 + 1)`

= `""^(2n)"C"_(r + 1) x^(r + 1)`

We have `""^(2n)"C"_(3r - 1) = ""^(2n)"C"_(r + 1)`

⇒ 3r – 1 + r + 1 = 2n   `....[because ""^n"C"_p = ""^n"C"_q ⇒ n = p + q]`

⇒ 4r = 2n

n = 2r

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 8: Binomial Theorem - Exercise [पृष्ठ १४४]

APPEARS IN

एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 11
अध्याय 8 Binomial Theorem
Exercise | Q 19 | पृष्ठ १४४

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Expand the expression: (1– 2x)5


Expand the expression (1– 2x)5


Expand the expression: `(x/3 + 1/x)^5`


Using binomial theorem, evaluate the following:

(99)5


Find (a + b)4 – (a – b)4. Hence, evaluate `(sqrt3 + sqrt2)^4 - (sqrt3 - sqrt2)^4`


Show that 9n+1 – 8n – 9 is divisible by 64, whenever n is a positive integer.


Find a if the coefficients of x2 and x3 in the expansion of (3 + ax)9 are equal.


Evaluate `(sqrt3 + sqrt2)^6 - (sqrt3 - sqrt2)^6`


Find the value of `(a^2 + sqrt(a^2 - 1))^4 + (a^2 - sqrt(a^2 -1))^4`


Find an approximation of (0.99)5 using the first three terms of its expansion.


Expand using Binomial Theorem `(1+ x/2 - 2/x)^4, x != 0`


Find the expansion of (3x2 – 2ax + 3a2)3 using binomial theorem.


Using binomial theorem determine which number is larger (1.2)4000 or 800?

 

Evaluate: `(x^2 - sqrt(1 - x^2))^4 + (x^2 + sqrt(1 - x^2))^4`


Show that `2^(4n + 4) - 15n - 16`, where n ∈ N is divisible by 225.


If n is a positive integer, find the coefficient of x–1 in the expansion of `(1 + x)^2 (1 + 1/x)^n`


If a1, a2, a3 and a4 are the coefficient of any four consecutive terms in the expansion of (1 + x)n, prove that `(a_1)/(a_1 + a_2) + (a_3)/(a_3 + a_4) = (2a_2)/(a_2 + a_3)`


The total number of terms in the expansion of (x + a)51 – (x – a)51 after simplification is ______.


If (1 – x + x2)n = a0 + a1 x + a2 x2 + ... + a2n x2n , then a0 + a2 + a4 + ... + a2n equals ______.


The coefficient of xp and xq (p and q are positive integers) in the expansion of (1 + x)p + q are ______.


If z = `sqrt(3)/2 + i^5/2 + sqrt(3)/2 - i^5/2`, then ______.


Find the coefficient of x in the expansion of (1 – 3x + 7x2)(1 – x)16.


Find the coefficient of x15 in the expansion of (x – x2)10.


Find the sixth term of the expansion `(y^(1/2) + x^(1/3))^"n"`, if the binomial coefficient of the third term from the end is 45.


If the coefficient of second, third and fourth terms in the expansion of (1 + x)2n are in A.P. Show that 2n2 – 9n + 7 = 0.


In the expansion of (x + a)n if the sum of odd terms is denoted by O and the sum of even term by E. Then prove that 4OE = (x + a)2n – (x – a)2n 


The total number of terms in the expansion of (x + a)100 + (x – a)100 after simplification is ______.


The number of terms in the expansion of (x + y + z)n ______.


The coefficient of a–6b4 in the expansion of `(1/a - (2b)/3)^10` is ______.


Let the coefficients of x–1 and x–3 in the expansion of `(2x^(1/5) - 1/x^(1/5))^15`, x > 0, be m and n respectively. If r is a positive integer such that mn2 = 15Cr, 2r, then the value of r is equal to ______.


If the coefficients of (2r + 4)th, (r – 2)th terms in the expansion of (1 + x)18 are equal, then r is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×