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Using Binomial Theorem, evaluate of the following:(102)5

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प्रश्न

Using Binomial Theorem, evaluate of the following:
(102)5

योग
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उत्तर

102 can be expressed as the sum or difference of two numbers whose powers are easier to calculate and then, Binomial Theorem can be applied.

It can be written that, 102 = 100 + 2

`(102)^5  =  (100 + 2)^5  = (100)^5  +  ^5C_1 (100)^4  xx 2  +  ^5C_2 (100)^3 2^2  + ^5C_3(100)^2  xx  2^3  +  ^5C_4(100)  xx  2^4  +  2^5`

= 5C0 (100)5 + 5C1 (100)4 (2) + 5C2 (100)3 (2)2 + 5C3 (100)2 (2)3 + 5C4 (100) (2)4 + 5C5 (2)5

= (100)5 + 5 (100)4 (2) + 10 (100)3 (2)2 + 10 (100)2 (2)3 + 5 (100) (2)4 + (2)5

= 10000000000 + 5 x 100000000 x 2 + 10 x 1000000 x 4 + 10 x 10000 x 8+5 x 100 x 16 + 32

= 10000000000 + 1000000000 + 40000000 + 800000 + 8000 + 32

= 11040808032

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अध्याय 7: Binomial Theorem - EXERCISE 7.1 [पृष्ठ १३३]

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एनसीईआरटी Mathematics [English] Class 11
अध्याय 7 Binomial Theorem
EXERCISE 7.1 | Q 7. | पृष्ठ १३३

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