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Find the sixth term of the expansion n(y12+x13)n, if the binomial coefficient of the third term from the end is 45. - Mathematics

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प्रश्न

Find the sixth term of the expansion `(y^(1/2) + x^(1/3))^"n"`, if the binomial coefficient of the third term from the end is 45.

योग
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उत्तर

The given expression is `(y^(1/2) + x^(1/3))^"n"`

Since the binomial coefficient of third term from the end = Binomial coefficient of third term from the beginning = nC2

nC2 = 45

⇒ `("n"("n" - 1))/2` = 45

⇒ n2 – n = 90

⇒ n2 – n – 90 = 0

⇒ n2 – 10n + 9n – 90 = 0

⇒ n(n – 10) + 9(n – 10) = 0

⇒ (n – 10)(n + 9) = 0

⇒ n = 10, n = –9

⇒ n = 10, n ≠ – 9

So, the given expression becomes `(y^(1/2) + x^(1/3))^10`

Sixth term is this expression T6 = T5+1

= `""^10"C"_5 (y^(1/2))^(10 - 5)  (x^(1/3))^5`

= `""^10"C"_5  y^(5/2) * x^(5/3)`

= `252  y^(5/2) x^(5/3)`

Hence, the required term = `252  y^(5/2) * x^(5/3)`

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अध्याय 8: Binomial Theorem - Exercise [पृष्ठ १४३]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
अध्याय 8 Binomial Theorem
Exercise | Q 8 | पृष्ठ १४३

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