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Using binomial theorem, evaluate the following: (99)5 - Mathematics

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प्रश्न

Using binomial theorem, evaluate the following:

(99)5

योग
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उत्तर

99 can be written as the sum or difference of two numbers whose powers are easier to calculate and then, Binomial Theorem can be applied.

It can be written that, 99 = 100 – 1

∴ `(99)^5 = (100 - 1)^5`

= `""^5C_0  (100)^5  +  ^5C_1  xx  (100)^4  xx  (- 1)  +  ^5C_2  xx  (100)^3  xx  (- 1)^2  +  ^5C_3  xx  (100)^2  xx  (-  1)^3  +  ^5C_4  xx  (100)  xx  (-4)^4  +  (-1)^5`

= 10000000000 – 5 x 100000000 + 10 x 1000000 – 10 x 10000 + 5 x 100 – 1

= 10000000000 – 500000000 + 10000000 – 100000 + 500 – 1

= 9509900499

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अध्याय 8: Binomial Theorem - Exercise 8.1 [पृष्ठ १६७]

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एनसीईआरटी Mathematics [English] Class 11
अध्याय 8 Binomial Theorem
Exercise 8.1 | Q 9 | पृष्ठ १६७

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