हिंदी

Using binomial theorem, evaluate the following: (99)5

Advertisements
Advertisements

प्रश्न

Using binomial theorem, evaluate the following:

(99)5

योग
Advertisements

उत्तर

99 can be written as the sum or difference of two numbers whose powers are easier to calculate and then, Binomial Theorem can be applied.

It can be written that, 99 = 100 – 1

∴ `(99)^5 = (100 - 1)^5`

= `""^5C_0  (100)^5  +  ^5C_1  xx  (100)^4  xx  (- 1)  +  ^5C_2  xx  (100)^3  xx  (- 1)^2  +  ^5C_3  xx  (100)^2  xx  (-  1)^3  +  ^5C_4  xx  (100)  xx  (-4)^4  +  (-1)^5`

= 10000000000 – 5 x 100000000 + 10 x 1000000 – 10 x 10000 + 5 x 100 – 1

= 10000000000 – 500000000 + 10000000 – 100000 + 500 – 1

= 9509900499

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Binomial Theorem - EXERCISE 7.1 [पृष्ठ १३३]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 11
अध्याय 7 Binomial Theorem
EXERCISE 7.1 | Q 9. | पृष्ठ १३३

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Expand the expression: (1– 2x)5


Expand the expression: (2x – 3)6


Expand the expression: `(x/3 + 1/x)^5`


Expand the expression: `(x + 1/x)^6`


Using Binomial Theorem, evaluate the following:

(96)3


Using Binomial Theorem, evaluate of the following:
(102)5


Using Binomial Theorem, indicate which number is larger (1.1)10000 or 1000.


Find (a + b)4 – (a – b)4. Hence, evaluate `(sqrt3 + sqrt2)^4 - (sqrt3 - sqrt2)^4`


Show that 9n+1 – 8n – 9 is divisible by 64, whenever n is a positive integer.


Prove that `sum_(r-0)^n 3^r  ""^nC_r = 4^n`


Find a if the coefficients of x2 and x3 in the expansion of (3 + ax)9 are equal.


Find the coefficient of x5 in the product (1 + 2x)6 (1 – x)7 using binomial theorem.


Expand using Binomial Theorem `(1+ x/2 - 2/x)^4, x != 0`


Find the expansion of (3x2 – 2ax + 3a2)3 using binomial theorem.


Using binomial theorem determine which number is larger (1.2)4000 or 800?

 

Find the value of (1.01)10 + (1 − 0.01)10 correct to 7 places of decimal.

 

Show that  \[2^{4n + 4} - 15n - 16\]  , where n ∈  \[\mathbb{N}\]  is divisible by 225.

 
  
  

Find the 4th term from the end in the expansion of `(x^3/2 - 2/x^2)^9`


Evaluate: `(x^2 - sqrt(1 - x^2))^4 + (x^2 + sqrt(1 - x^2))^4`


Determine whether the expansion of `(x^2 - 2/x)^18` will contain a term containing x10?


Find the term independent of x in the expansion of `(sqrt(x)/sqrt(3) + sqrt(3)/(2x^2))^10`.


Show that `2^(4n + 4) - 15n - 16`, where n ∈ N is divisible by 225.


Which of the following is larger? 9950 + 10050  or 10150


Find the coefficient of x50 after simplifying and collecting the like terms in the expansion of (1 + x)1000 + x(1 + x)999 + x2(1 + x)998 + ... + x1000 .


The coefficient of xp and xq (p and q are positive integers) in the expansion of (1 + x)p + q are ______.


The number of terms in the expansion of (a + b + c)n, where n ∈ N is ______.


Find the coefficient of x4 in the expansion of (1 + x + x2 + x3)11.


In the expansion of (x + a)n if the sum of odd terms is denoted by O and the sum of even term by E. Then prove that O2 – E2 = (x2 – a2)n 


In the expansion of (x + a)n if the sum of odd terms is denoted by O and the sum of even term by E. Then prove that 4OE = (x + a)2n – (x – a)2n 


The two successive terms in the expansion of (1 + x)24 whose coefficients are in the ratio 1:4 are ______.


The number of terms in the expansion of (x + y + z)n ______.


The sum of the last eight coefficients in the expansion of (1 + x)16 is equal to ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×