हिंदी

Find the term independent of x in the expansion of (x3+32x2)10.

Advertisements
Advertisements

प्रश्न

Find the term independent of x in the expansion of `(sqrt(x)/sqrt(3) + sqrt(3)/(2x^2))^10`.

योग
Advertisements

उत्तर

Let (r + 1)th term be independent of x which is given by

Tr+1 = `""^10"C"_r  sqrt(x/3)^(10 - r)  sqrt(3)^r/(2x^2)`

= `""^10"C"_r  x^((10 - r)/2)/3  3^(r/2)  1/(2^r  x^(2r))`

= `""^10"C"_r  3^(r/2 - (10 - r)/2)  2^(-r)  x^((10 - r)/2 - 2r)` 

Since the term is independent of x, we have

`(10 - r)/2 - 2r` = 0

⇒ r = 2

Hence 3rd term is independent of x and its value is given by

T3 = `""^10"C"_2  (3^(-3))/4`

= `(10 xx 9)/(2 xx 1) xx 1/(9 xx 12)`

= `5/12`

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 8: Binomial Theorem - Solved Examples [पृष्ठ १३४]

APPEARS IN

एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 11
अध्याय 8 Binomial Theorem
Solved Examples | Q 7 | पृष्ठ १३४

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Expand the expression: (1– 2x)5


Expand the expression (1– 2x)5


Expand the expression: `(2/x - x/2)^5`


Expand the expression: (2x – 3)6


Expand the expression: `(x/3 + 1/x)^5`


Find (x + 1)6 + (x – 1)6. Hence or otherwise evaluate `(sqrt2 + 1)^6 + (sqrt2 -1)^6`


Find ab and n in the expansion of (a + b)n if the first three terms of the expansion are 729, 7290 and 30375, respectively.


Find the coefficient of x5 in the product (1 + 2x)6 (1 – x)7 using binomial theorem.


Evaluate `(sqrt3 + sqrt2)^6 - (sqrt3 - sqrt2)^6`


If n is a positive integer, prove that \[3^{3n} - 26n - 1\]  is divisible by 676.

 
 

Find the value of (1.01)10 + (1 − 0.01)10 correct to 7 places of decimal.

 

Expand the following (1 – x + x2)4 


Determine whether the expansion of `(x^2 - 2/x)^18` will contain a term containing x10?


If n is a positive integer, find the coefficient of x–1 in the expansion of `(1 + x)^2 (1 + 1/x)^n`


Which of the following is larger? 9950 + 10050  or 10150


Find the coefficient of x50 after simplifying and collecting the like terms in the expansion of (1 + x)1000 + x(1 + x)999 + x2(1 + x)998 + ... + x1000 .


If a1, a2, a3 and a4 are the coefficient of any four consecutive terms in the expansion of (1 + x)n, prove that `(a_1)/(a_1 + a_2) + (a_3)/(a_3 + a_4) = (2a_2)/(a_2 + a_3)`


The total number of terms in the expansion of (x + a)51 – (x – a)51 after simplification is ______.


If the coefficients of x7 and x8 in `2 + x^n/3` are equal, then n is ______.


If (1 – x + x2)n = a0 + a1 x + a2 x2 + ... + a2n x2n , then a0 + a2 + a4 + ... + a2n equals ______.


Find the coefficient of x15 in the expansion of (x – x2)10.


In the expansion of (x + a)n if the sum of odd terms is denoted by O and the sum of even term by E. Then prove that O2 – E2 = (x2 – a2)n 


In the expansion of (x + a)n if the sum of odd terms is denoted by O and the sum of even term by E. Then prove that 4OE = (x + a)2n – (x – a)2n 


The total number of terms in the expansion of (x + a)100 + (x – a)100 after simplification is ______.


Given the integers r > 1, n > 2, and coefficients of (3r)th and (r + 2)nd terms in the binomial expansion of (1 + x)2n are equal, then ______.


The coefficient of a–6b4 in the expansion of `(1/a - (2b)/3)^10` is ______.


Let the coefficients of x–1 and x–3 in the expansion of `(2x^(1/5) - 1/x^(1/5))^15`, x > 0, be m and n respectively. If r is a positive integer such that mn2 = 15Cr, 2r, then the value of r is equal to ______.


The sum of the last eight coefficients in the expansion of (1 + x)16 is equal to ______.


If the coefficients of (2r + 4)th, (r – 2)th terms in the expansion of (1 + x)18 are equal, then r is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×