English

The two successive terms in the expansion of (1 + x)24 whose coefficients are in the ratio 1:4 are ______.

Advertisements
Advertisements

Question

The two successive terms in the expansion of (1 + x)24 whose coefficients are in the ratio 1:4 are ______.

Options

  • 3rd and 4th

  • 4th and 5th

  • 5th and 6th

  • 6th and 7th

MCQ
Fill in the Blanks
Advertisements

Solution

The two successive terms in the expansion of (1 + x)24 whose coefficients are in the ratio 1:4 are 5th and 6th.

Explanation:

Let rth and (r + 1)th be two successive terms in the expansion (1 + x)24

∴ `"T"_(r + 1) = ""^24"C"_r * x^r`

`"T"_(r + 2) = "T"_(r + 1 + 1) = ""^24"C"_(r + 1) x^(r + 1)`

 We have `(""^24"C"_r)/(""^24"C"_(r + 1)) = 1/4`

⇒ `((24!)/(r!(24 - r)!))/((24!)/((r + 1)!(24 - r - 1)!)) = 1/4`

⇒ `(24!)/(r!(24 - r)!) xx ((r - 1)!(24 - r - 1)!)/(24!) = 1/4`

⇒ `((r + 1) * r!(24 - r - 1)!)/(r!(24 - r)(24 - r - 1)!) = 1/4`

⇒ `(r + 1)/(24 - r) = 1/4`

⇒ 4r + 4 = 24 – r

⇒ 5r = 20

⇒ r = 4

∴ T4+1 = T5 and T4+2 = T6

shaalaa.com
  Is there an error in this question or solution?
Chapter 8: Binomial Theorem - Exercise [Page 144]

APPEARS IN

NCERT Exemplar Mathematics [English] Class 11
Chapter 8 Binomial Theorem
Exercise | Q 20 | Page 144

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Expand the expression: (1– 2x)5


Expand the expression: `(2/x - x/2)^5`


Expand the expression: `(x/3 + 1/x)^5`


Using Binomial Theorem, evaluate of the following:
(102)5


Using binomial theorem, evaluate f the following:

(101)4


Using Binomial Theorem, indicate which number is larger (1.1)10000 or 1000.


Find ab and n in the expansion of (a + b)n if the first three terms of the expansion are 729, 7290 and 30375, respectively.


Find the value of `(a^2 + sqrt(a^2 - 1))^4 + (a^2 - sqrt(a^2 -1))^4`


Find an approximation of (0.99)5 using the first three terms of its expansion.


Find the expansion of (3x2 – 2ax + 3a2)3 using binomial theorem.


Using binomial theorem determine which number is larger (1.2)4000 or 800?

 

Find the value of (1.01)10 + (1 − 0.01)10 correct to 7 places of decimal.

 

Show that  \[2^{4n + 4} - 15n - 16\]  , where n ∈  \[\mathbb{N}\]  is divisible by 225.

 
  
  

Find the rth term in the expansion of `(x + 1/x)^(2r)`


Evaluate: `(x^2 - sqrt(1 - x^2))^4 + (x^2 + sqrt(1 - x^2))^4`


Find the coefficient of x11 in the expansion of `(x^3 - 2/x^2)^12`


Which of the following is larger? 9950 + 10050  or 10150


Find the coefficient of x50 after simplifying and collecting the like terms in the expansion of (1 + x)1000 + x(1 + x)999 + x2(1 + x)998 + ... + x1000 .


The total number of terms in the expansion of (x + a)51 – (x – a)51 after simplification is ______.


If the coefficients of x7 and x8 in `2 + x^n/3` are equal, then n is ______.


If (1 – x + x2)n = a0 + a1 x + a2 x2 + ... + a2n x2n , then a0 + a2 + a4 + ... + a2n equals ______.


If z = `sqrt(3)/2 + i^5/2 + sqrt(3)/2 - i^5/2`, then ______.


Find the coefficient of x15 in the expansion of (x – x2)10.


Find the sixth term of the expansion `(y^(1/2) + x^(1/3))^"n"`, if the binomial coefficient of the third term from the end is 45.


If the coefficient of second, third and fourth terms in the expansion of (1 + x)2n are in A.P. Show that 2n2 – 9n + 7 = 0.


Find the coefficient of x4 in the expansion of (1 + x + x2 + x3)11.


In the expansion of (x + a)n if the sum of odd terms is denoted by O and the sum of even term by E. Then prove that O2 – E2 = (x2 – a2)n 


In the expansion of (x + a)n if the sum of odd terms is denoted by O and the sum of even term by E. Then prove that 4OE = (x + a)2n – (x – a)2n 


The total number of terms in the expansion of (x + a)100 + (x – a)100 after simplification is ______.


The number of terms in the expansion of (x + y + z)n ______.


The sum of the last eight coefficients in the expansion of (1 + x)16 is equal to ______.


If the coefficients of (2r + 4)th, (r – 2)th terms in the expansion of (1 + x)18 are equal, then r is ______.


The positive integer just greater than (1 + 0.0001)10000 is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×