English

The two successive terms in the expansion of (1 + x)24 whose coefficients are in the ratio 1:4 are ______.

Advertisements
Advertisements

Question

The two successive terms in the expansion of (1 + x)24 whose coefficients are in the ratio 1:4 are ______.

Options

  • 3rd and 4th

  • 4th and 5th

  • 5th and 6th

  • 6th and 7th

MCQ
Fill in the Blanks
Advertisements

Solution

The two successive terms in the expansion of (1 + x)24 whose coefficients are in the ratio 1:4 are 5th and 6th.

Explanation:

Let rth and (r + 1)th be two successive terms in the expansion (1 + x)24

∴ `"T"_(r + 1) = ""^24"C"_r * x^r`

`"T"_(r + 2) = "T"_(r + 1 + 1) = ""^24"C"_(r + 1) x^(r + 1)`

 We have `(""^24"C"_r)/(""^24"C"_(r + 1)) = 1/4`

⇒ `((24!)/(r!(24 - r)!))/((24!)/((r + 1)!(24 - r - 1)!)) = 1/4`

⇒ `(24!)/(r!(24 - r)!) xx ((r - 1)!(24 - r - 1)!)/(24!) = 1/4`

⇒ `((r + 1) * r!(24 - r - 1)!)/(r!(24 - r)(24 - r - 1)!) = 1/4`

⇒ `(r + 1)/(24 - r) = 1/4`

⇒ 4r + 4 = 24 – r

⇒ 5r = 20

⇒ r = 4

∴ T4+1 = T5 and T4+2 = T6

shaalaa.com
  Is there an error in this question or solution?
Chapter 8: Binomial Theorem - Exercise [Page 144]

APPEARS IN

NCERT Exemplar Mathematics Exemplar [English] Class 11
Chapter 8 Binomial Theorem
Exercise | Q 20 | Page 144

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Expand the expression: (1– 2x)5


Expand the expression (1– 2x)5


Expand the expression: (2x – 3)6


Expand the expression: `(x/3 + 1/x)^5`


Using Binomial Theorem, evaluate the following:

(96)3


Using Binomial Theorem, evaluate of the following:
(102)5


Using binomial theorem, evaluate the following:

(99)5


Using Binomial Theorem, indicate which number is larger (1.1)10000 or 1000.


Find (x + 1)6 + (x – 1)6. Hence or otherwise evaluate `(sqrt2 + 1)^6 + (sqrt2 -1)^6`


Prove that `sum_(r-0)^n 3^r  ""^nC_r = 4^n`


Find the coefficient of x5 in the product (1 + 2x)6 (1 – x)7 using binomial theorem.


If a and b are distinct integers, prove that a – b is a factor of an – bn, whenever n is a positive integer.

[Hint: write an = (a – b + b)n and expand]


Expand using Binomial Theorem `(1+ x/2 - 2/x)^4, x != 0`


Using binomial theorem determine which number is larger (1.2)4000 or 800?

 

Expand the following (1 – x + x2)4 


Evaluate: `(x^2 - sqrt(1 - x^2))^4 + (x^2 + sqrt(1 - x^2))^4`


Show that `2^(4n + 4) - 15n - 16`, where n ∈ N is divisible by 225.


If n is a positive integer, find the coefficient of x–1 in the expansion of `(1 + x)^2 (1 + 1/x)^n`


Which of the following is larger? 9950 + 10050  or 10150


Find the coefficient of x50 after simplifying and collecting the like terms in the expansion of (1 + x)1000 + x(1 + x)999 + x2(1 + x)998 + ... + x1000 .


The number of terms in the expansion of (a + b + c)n, where n ∈ N is ______.


Find the coefficient of x in the expansion of (1 – 3x + 7x2)(1 – x)16.


If the coefficient of second, third and fourth terms in the expansion of (1 + x)2n are in A.P. Show that 2n2 – 9n + 7 = 0.


In the expansion of (x + a)n if the sum of odd terms is denoted by O and the sum of even term by E. Then prove that O2 – E2 = (x2 – a2)n 


The coefficient of a–6b4 in the expansion of `(1/a - (2b)/3)^10` is ______.


Number of terms in the expansion of (a + b)n where n ∈ N is one less than the power n.


Let the coefficients of x–1 and x–3 in the expansion of `(2x^(1/5) - 1/x^(1/5))^15`, x > 0, be m and n respectively. If r is a positive integer such that mn2 = 15Cr, 2r, then the value of r is equal to ______.


If the coefficients of (2r + 4)th, (r – 2)th terms in the expansion of (1 + x)18 are equal, then r is ______.


Let `(5 + 2sqrt(6))^n` = p + f where n∈N and p∈N and 0 < f < 1 then the value of f2 – f + pf – p is ______. 


The positive integer just greater than (1 + 0.0001)10000 is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×