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Expand the expression: (2x-x2)5

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Question

Expand the expression: `(2/x - x/2)^5`

Sum
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Solution

By using Binomial Theorem, the expression `(2/x - x/2)^5` can be explained as

`(2/x - x/2)^5  =  ^5C_0 (2/x)^5 -  ^5C_1  (2/x)^4  (x/2)  +  ^5C_2  (2/x)^3  (x/2)^2`

- `""^5C_3  (2/x)^2  (x/2)^3  +  ^5C_4 (2/x) (x/2)^4  -  ^5C_5  (x/2)^5`

= `(32)/x^5  - 5 (16/(x^4)) (x/2)  + 10 (8/x^3) (x^2/4) - 10 (4/x^2) (x^3/8) +5 (2/x)(x^4/16) - x^5/32`

= `32/x^5  - 40/x^3  + 20/x  - 5x + 5/8 x^3  - x^5/32`

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Chapter 7: Binomial Theorem - EXERCISE 7.1 [Page 132]

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NCERT Mathematics [English] Class 11
Chapter 7 Binomial Theorem
EXERCISE 7.1 | Q 2. | Page 132

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