English

The coefficient of a–6b4 in the expansion of (1a-2b3)10 is ______. - Mathematics

Advertisements
Advertisements

Question

The coefficient of a–6b4 in the expansion of `(1/a - (2b)/3)^10` is ______.

Fill in the Blanks
Advertisements

Solution

The coefficient of a–6b4 in the expansion of `(1/a - (2b)/3)^10` is `1120/27`.

Explanation:

The given expansion is `(1/a - (2b)/3)^10`

From a–6b4 

We can take r = 4

∴ T5 = T4+1

= `""^10"C"_4 (1/a)^(10 - 4) (- (2b)/3)^4`

= `""^10"C"_4 (1/a)^6 ((-2)/3)^4 * b^4`

= `(10*9*8*7)/(4*3*2*1) xx 16/81 * a^-6b^4`

= `210 xx 16/81 a^-6b^4`

= `1120/27 a^-6b^4`

shaalaa.com
  Is there an error in this question or solution?
Chapter 8: Binomial Theorem - Exercise [Page 146]

APPEARS IN

NCERT Exemplar Mathematics [English] Class 11
Chapter 8 Binomial Theorem
Exercise | Q 29 | Page 146

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Expand the expression: (1– 2x)5


Expand the expression: `(2/x - x/2)^5`


Expand the expression: `(x + 1/x)^6`


Using Binomial Theorem, evaluate the following:

(96)3


Using Binomial Theorem, evaluate of the following:
(102)5


Using binomial theorem, evaluate f the following:

(101)4


Using Binomial Theorem, indicate which number is larger (1.1)10000 or 1000.


Find (a + b)4 – (a – b)4. Hence, evaluate `(sqrt3 + sqrt2)^4 - (sqrt3 - sqrt2)^4`


Find (x + 1)6 + (x – 1)6. Hence or otherwise evaluate `(sqrt2 + 1)^6 + (sqrt2 -1)^6`


Find ab and n in the expansion of (a + b)n if the first three terms of the expansion are 729, 7290 and 30375, respectively.


Find a if the coefficients of x2 and x3 in the expansion of (3 + ax)9 are equal.


Evaluate `(sqrt3 + sqrt2)^6 - (sqrt3 - sqrt2)^6`


Find the value of `(a^2 + sqrt(a^2 - 1))^4 + (a^2 - sqrt(a^2 -1))^4`


Expand using Binomial Theorem `(1+ x/2 - 2/x)^4, x != 0`


Find the expansion of (3x2 – 2ax + 3a2)3 using binomial theorem.


Show that  \[2^{4n + 4} - 15n - 16\]  , where n ∈  \[\mathbb{N}\]  is divisible by 225.

 
  
  

Find the 4th term from the end in the expansion of `(x^3/2 - 2/x^2)^9`


Find the coefficient of x11 in the expansion of `(x^3 - 2/x^2)^12`


Find the term independent of x in the expansion of `(sqrt(x)/sqrt(3) + sqrt(3)/(2x^2))^10`.


Show that `2^(4n + 4) - 15n - 16`, where n ∈ N is divisible by 225.


If n is a positive integer, find the coefficient of x–1 in the expansion of `(1 + x)^2 (1 + 1/x)^n`


If a1, a2, a3 and a4 are the coefficient of any four consecutive terms in the expansion of (1 + x)n, prove that `(a_1)/(a_1 + a_2) + (a_3)/(a_3 + a_4) = (2a_2)/(a_2 + a_3)`


The total number of terms in the expansion of (x + a)51 – (x – a)51 after simplification is ______.


If the coefficients of x7 and x8 in `2 + x^n/3` are equal, then n is ______.


The coefficient of xp and xq (p and q are positive integers) in the expansion of (1 + x)p + q are ______.


The number of terms in the expansion of (a + b + c)n, where n ∈ N is ______.


Find the coefficient of x in the expansion of (1 – 3x + 7x2)(1 – x)16.


Find the coefficient of x4 in the expansion of (1 + x + x2 + x3)11.


The two successive terms in the expansion of (1 + x)24 whose coefficients are in the ratio 1:4 are ______.


The number of terms in the expansion of (x + y + z)n ______.


Number of terms in the expansion of (a + b)n where n ∈ N is one less than the power n.


Let the coefficients of x–1 and x–3 in the expansion of `(2x^(1/5) - 1/x^(1/5))^15`, x > 0, be m and n respectively. If r is a positive integer such that mn2 = 15Cr, 2r, then the value of r is equal to ______.


If the coefficients of (2r + 4)th, (r – 2)th terms in the expansion of (1 + x)18 are equal, then r is ______.


Let `(5 + 2sqrt(6))^n` = p + f where n∈N and p∈N and 0 < f < 1 then the value of f2 – f + pf – p is ______. 


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×