English

Using Binomial Theorem, evaluate the following: (96)3

Advertisements
Advertisements

Question

Using Binomial Theorem, evaluate the following:

(96)3

Sum
Advertisements

Solution

96 can be expressed as the sum or difference of two numbers whose powers are easier to calculate and then, binomial theorem can be applied.

It can be written that, 96 = 100 – 4

∴ (96)3 = (100 - 4)3

= 3C0 (100)3 - 3C1 (100)2 (4) + 3C2 (100) (4)2 - 3C3 (4)3

= (100)3 - 3(100)2 (4) + 3(100) (4)2 - (4)3

= 1000000 - 120000 + 4800 - 64

= 884736

shaalaa.com
  Is there an error in this question or solution?
Chapter 7: Binomial Theorem - EXERCISE 7.1 [Page 133]

APPEARS IN

NCERT Mathematics [English] Class 11
Chapter 7 Binomial Theorem
EXERCISE 7.1 | Q 6. | Page 133

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Expand the expression (1– 2x)5


Expand the expression: (2x – 3)6


Expand the expression: `(x/3 + 1/x)^5`


Using binomial theorem, evaluate f the following:

(101)4


Find (x + 1)6 + (x – 1)6. Hence or otherwise evaluate `(sqrt2 + 1)^6 + (sqrt2 -1)^6`


Find ab and n in the expansion of (a + b)n if the first three terms of the expansion are 729, 7290 and 30375, respectively.


Find a if the coefficients of x2 and x3 in the expansion of (3 + ax)9 are equal.


Evaluate `(sqrt3 + sqrt2)^6 - (sqrt3 - sqrt2)^6`


Find the value of `(a^2 + sqrt(a^2 - 1))^4 + (a^2 - sqrt(a^2 -1))^4`


Expand using Binomial Theorem `(1+ x/2 - 2/x)^4, x != 0`


Find the expansion of (3x2 – 2ax + 3a2)3 using binomial theorem.


If n is a positive integer, prove that \[3^{3n} - 26n - 1\]  is divisible by 676.

 
 

Using binomial theorem determine which number is larger (1.2)4000 or 800?

 

Find the value of (1.01)10 + (1 − 0.01)10 correct to 7 places of decimal.

 

Show that  \[2^{4n + 4} - 15n - 16\]  , where n ∈  \[\mathbb{N}\]  is divisible by 225.

 
  
  

Expand the following (1 – x + x2)4 


Find the 4th term from the end in the expansion of `(x^3/2 - 2/x^2)^9`


Find the term independent of x in the expansion of `(sqrt(x)/sqrt(3) + sqrt(3)/(2x^2))^10`.


Show that `2^(4n + 4) - 15n - 16`, where n ∈ N is divisible by 225.


Which of the following is larger? 9950 + 10050  or 10150


If a1, a2, a3 and a4 are the coefficient of any four consecutive terms in the expansion of (1 + x)n, prove that `(a_1)/(a_1 + a_2) + (a_3)/(a_3 + a_4) = (2a_2)/(a_2 + a_3)`


The total number of terms in the expansion of (x + a)51 – (x – a)51 after simplification is ______.


The number of terms in the expansion of (a + b + c)n, where n ∈ N is ______.


Find the coefficient of x in the expansion of (1 – 3x + 7x2)(1 – x)16.


Find the coefficient of x15 in the expansion of (x – x2)10.


In the expansion of (x + a)n if the sum of odd terms is denoted by O and the sum of even term by E. Then prove that 4OE = (x + a)2n – (x – a)2n 


The total number of terms in the expansion of (x + a)100 + (x – a)100 after simplification is ______.


Given the integers r > 1, n > 2, and coefficients of (3r)th and (r + 2)nd terms in the binomial expansion of (1 + x)2n are equal, then ______.


The coefficient of a–6b4 in the expansion of `(1/a - (2b)/3)^10` is ______.


Let the coefficients of x–1 and x–3 in the expansion of `(2x^(1/5) - 1/x^(1/5))^15`, x > 0, be m and n respectively. If r is a positive integer such that mn2 = 15Cr, 2r, then the value of r is equal to ______.


Let `(5 + 2sqrt(6))^n` = p + f where n∈N and p∈N and 0 < f < 1 then the value of f2 – f + pf – p is ______. 


The positive integer just greater than (1 + 0.0001)10000 is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×