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Find the coefficient of x4 in the expansion of (1 + x + x2 + x3)11.

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Question

Find the coefficient of x4 in the expansion of (1 + x + x2 + x3)11.

Sum
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Solution

Given expression is (1 + x + x2 + x3)11

= [(1 + x) + x2 (1 + x)]11

= [(1 + x)(1 + x2)]11

= (1 + x)11 · (1 + x2)11

Expanding the above expression, we get

(11C0 + 11C1x + 11C2x2 + 11C3x3 + 11C4x4 + …) · (11C0 + 11C1x2 + 11C2x4 +)

= (1 + 11x + 55x2 + 165x3 + 330x4 …) · (1 + 11x2 + 55x4 + …)

Collecting the terms containing x4, we get

(55 + 605 + 330)x4 = 990x4

Hence, the coefficient of x4 = 990

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Chapter 8: Binomial Theorem - Exercise [Page 143]

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NCERT Exemplar Mathematics Exemplar [English] Class 11
Chapter 8 Binomial Theorem
Exercise | Q 11 | Page 143

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