English

Which of the following is larger? 9950 + 10050 or 10150

Advertisements
Advertisements

Question

Which of the following is larger? 9950 + 10050  or 10150

Sum
Advertisements

Solution

We have (101)50 = (100 + 1)50

= `100^50 + 50(100)^49 + (50*49)/(2*1) (100)^48 + (50*49*48)/(3*2*1) (100)^47 +` ......(1)

Similarly 9950 = (100 – 1)50

= `100^50 - 50 * 100^59 + (50*49)/(2*1) (100)^48 - (50*49*48)/(3*2*1) (100)^47 +`  ....(2)

Subtracting (2) from (1), we get

10150 – 9950 = `2  50*(100)^49 + (50*49*48)/(3*2*1) 100^47 +`  ....

⇒ 10150 – 9950 = `100^50 + 2  (50*49*48)/(3*2*1)  10^47 +`  ....

⇒ 10150 – 9950 > 10050

Hence 10150 > 9950 + 10050

shaalaa.com
  Is there an error in this question or solution?
Chapter 8: Binomial Theorem - Solved Examples [Page 137]

APPEARS IN

NCERT Exemplar Mathematics [English] Class 11
Chapter 8 Binomial Theorem
Solved Examples | Q 13 | Page 137

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Expand the expression: (1– 2x)5


Expand the expression: `(x/3 + 1/x)^5`


Expand the expression: `(x + 1/x)^6`


Using Binomial Theorem, evaluate of the following:
(102)5


Using binomial theorem, evaluate f the following:

(101)4


Find (a + b)4 – (a – b)4. Hence, evaluate `(sqrt3 + sqrt2)^4 - (sqrt3 - sqrt2)^4`


Find a if the coefficients of x2 and x3 in the expansion of (3 + ax)9 are equal.


Find the coefficient of x5 in the product (1 + 2x)6 (1 – x)7 using binomial theorem.


Evaluate `(sqrt3 + sqrt2)^6 - (sqrt3 - sqrt2)^6`


Find the value of `(a^2 + sqrt(a^2 - 1))^4 + (a^2 - sqrt(a^2 -1))^4`


Expand using Binomial Theorem `(1+ x/2 - 2/x)^4, x != 0`


If n is a positive integer, prove that \[3^{3n} - 26n - 1\]  is divisible by 676.

 
 

Find the value of (1.01)10 + (1 − 0.01)10 correct to 7 places of decimal.

 

Show that  \[2^{4n + 4} - 15n - 16\]  , where n ∈  \[\mathbb{N}\]  is divisible by 225.

 
  
  

Find the 4th term from the end in the expansion of `(x^3/2 - 2/x^2)^9`


Evaluate: `(x^2 - sqrt(1 - x^2))^4 + (x^2 + sqrt(1 - x^2))^4`


Find the coefficient of x11 in the expansion of `(x^3 - 2/x^2)^12`


Find the term independent of x in the expansion of `(sqrt(x)/sqrt(3) + sqrt(3)/(2x^2))^10`.


If a1, a2, a3 and a4 are the coefficient of any four consecutive terms in the expansion of (1 + x)n, prove that `(a_1)/(a_1 + a_2) + (a_3)/(a_3 + a_4) = (2a_2)/(a_2 + a_3)`


The coefficient of xp and xq (p and q are positive integers) in the expansion of (1 + x)p + q are ______.


If z = `sqrt(3)/2 + i^5/2 + sqrt(3)/2 - i^5/2`, then ______.


Find the sixth term of the expansion `(y^(1/2) + x^(1/3))^"n"`, if the binomial coefficient of the third term from the end is 45.


Find the coefficient of x4 in the expansion of (1 + x + x2 + x3)11.


In the expansion of (x + a)n if the sum of odd terms is denoted by O and the sum of even term by E. Then prove that 4OE = (x + a)2n – (x – a)2n 


The two successive terms in the expansion of (1 + x)24 whose coefficients are in the ratio 1:4 are ______.


The coefficient of a–6b4 in the expansion of `(1/a - (2b)/3)^10` is ______.


Number of terms in the expansion of (a + b)n where n ∈ N is one less than the power n.


Let the coefficients of x–1 and x–3 in the expansion of `(2x^(1/5) - 1/x^(1/5))^15`, x > 0, be m and n respectively. If r is a positive integer such that mn2 = 15Cr, 2r, then the value of r is equal to ______.


Let `(5 + 2sqrt(6))^n` = p + f where n∈N and p∈N and 0 < f < 1 then the value of f2 – f + pf – p is ______. 


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×