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Find an approximation of (0.99)5 using the first three terms of its expansion.

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Question

Find an approximation of (0.99)5 using the first three terms of its expansion.

Sum
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Solution

0.99 = 1 - 0.01

∴ (0.99)5  = (1 - 0.01)5

= 5C0(1)5 - 5C1 (1)4 (0. 01) + 5C2 (1)3 (0.01)2

= 1 – 5 x 0.01 + 10 x 0.0001

= 1 – 0.05 + 0.001

= 1.001 – 0.05

= 0.951

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Chapter 7: Binomial Theorem - Miscellaneous Exercise [Page 131]

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NCERT Mathematics [English] Class 11
Chapter 7 Binomial Theorem
Miscellaneous Exercise | Q 4. | Page 131

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