Advertisements
Advertisements
Question
Two resistors of 4Ω and 6Ω are connected in parallel to a cell to draw 0.5 A current from the cell. Calculate the current in each resistor.
Advertisements
Solution
`1/"R" = 1/4 + 1/6`
R = 2.4 Ω
⇒ V = IR
V = 0.5 × 2.4 = 1.2 V
i1 = `"V"/"R"_1`
`= 1.2/4 = 0.3 "A"`
i2 = `1.2/6 = 0.2` A
RELATED QUESTIONS
Find the expression for the resistors connected in series and write the two characteristics of it. (Draw figure).
Judge the equivalent resistance when the following are connected in parallel − (a) 1 Ω and 106Ω, (b) 1 Ω and 103Ω and 106Ω.
Find the equivalent resistance between A and B

How does the resistance of a wire change when:
its diameter is tripled?
You are supplied with a number of 100 Ω resistors. How could you combine some of these resistors to make a 250 Ω resistor?
The voltage applied to a given rheostat is made four times its initial value. By what factor will be resistance of the rheostat change?
Illustrate-combination of cells e.g., three cells, in series, explaining the combination briefly. Obtain an expression for current ‘i’ in the combination.
What should be the length of a nickel wire of area of cross-section 3 mm2 used for making a rheostat of 750 ohm? (ρ of nickle = 0.069 Ohm mm2/m)
In an electrical circuit, two resistors of 2 Ω and 4 Ω respectively are connected in series to a 6 V battery. The heat dissipated by the 4 Ω resistor in 5 s will be ______.
