Advertisements
Advertisements
Question
Two resistors of 4Ω and 6Ω are connected in parallel to a cell to draw 0.5 A current from the cell. Calculate the current in each resistor.
Advertisements
Solution
`1/"R" = 1/4 + 1/6`
R = 2.4 Ω
⇒ V = IR
V = 0.5 × 2.4 = 1.2 V
i1 = `"V"/"R"_1`
`= 1.2/4 = 0.3 "A"`
i2 = `1.2/6 = 0.2` A
APPEARS IN
RELATED QUESTIONS
Find the expression for resistors connected in series.
Write any two characteristics of a series combination of resistors.
Name the material which is used for making the heating element of an electric iron.
V = IRTwo resistances X and Y are connected turn by turn : (i) in parallel, and (ii) series. In which case the resultant resistance will be less than either of the individual resistances?R = R1+ R2+ R3
Calculate the combined resistance in each case:
Draw a V-I graph for a conductor at two different temperatures. What conclusion do you draw from your graph for the variation of resistance of conductor with temperature?
State a relation between electrical power, resistance and potential difference in an electrical circuit.
Two resistors having 2Ω and 3Ω resistance are connected—(i) in series, and (ii) in parallel. Find the equivalent resistance in each case.
In an electrical circuit, two resistors of 2 Ω and 4 Ω respectively are connected in series to a 6 V battery. The heat dissipated by the 4 Ω resistor in 5 s will be ______.
