Advertisements
Advertisements
Question
Two resistors of 4Ω and 6 Ω are connected in parallel to a cell to draw 0.5 A current from the cell.
(i) Draw a labelled circuit diagram showing the above arrangement.
(ii) Calculate the current in each resistor. What is an Ohmic resistor?
Advertisements
Solution
i.
The parallel combination of two resistors 4 Ω and 6 Ω that draws a current of 0.5 A from the cell is as shown below.

ii.
In parallel combination of resistors potential difference across each resistor is same as the potential difference across the terminals of the battery.
Here current drawn from cell, I = 0.5 A
The effective resistance `1/R=1/R_1+1/R_2`
Here R1=4Ω and R2=6Ω
`therefore 1/R=1/4+1/6`
`therefore 1/R=5/12`
`therefore R=12/5`
`therefore R=2.4 Omega`
APPEARS IN
RELATED QUESTIONS
Find the expression for resistors connected in series.
Judge the equivalent resistance when the following are connected in parallel − (a) 1 Ω and 106Ω, (b) 1 Ω and 103Ω and 106Ω.
When a 4 Ω resistor is connected across the terminals of a 12 V battery, the number of coulombs passing through the resistor per second is:
(a) 0.3
(b) 3
(c) 4
(d) 12
You are supplied with a number of 100 Ω resistors. How could you combine some of these resistors to make a 250 Ω resistor?
Write an expression for the resistance of a conducting wire in terms of its length and area of cross-section.
Write an expression for calculating electrical power in terms of current and resistance.
2Ω resistor A, 1Ω resistor B and 4Ω resistor C are connected in parallel. The combination is connected across a 2V battery of negligible resistance. Draw the diagram of the arrangement and calculate:
(i) The current in each resistor A and C,
(ii) The current through battery.
Illustrate-combination of cells e.g., three cells, in parallel, explaining the combination briefly. Obtain an expression for current ‘i’ in the combination.
With the help of a circuit diagram derive the formula for the resultant resistance of three resistances connected:
- in series and
- in parallel
Two electric bulbs have resistances in the ratio 1 : 2. If they are joined in series, the energy consumed in them is in the ratio:
