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Question
Two poles of height 9m and 14m stand on a plane ground. If the distance between their 12m, find the distance between their tops.
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Solution
Let AB and CD be the two poles of height 14m and 9m respectively.
It is given that BD = 12m
∴ CE = 12m
Now,
AE = AB - BE
= 14m - 9m = 5m
Using Pythagoras theorem in ΔACE,
AC2 = AE2 + CE2
= (5m)2 + (12m)2
= 25m2 = 144m2
= 169m2
= 13m2
⇒ AC = 13m
Thus, the distance between the tops of the poles is 13m.
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