Advertisements
Advertisements
Question
In triangle PQR, angle Q = 90°, find: PR, if PQ = 8 cm and QR = 6 cm
Advertisements
Solution
Given:
PQ = 8 cm
QR = 6 cm
PR =?
∠PQR = 90°
According to Pythagoras Theorem,
(PR)2 = (PQ)2 + (QR)2
PR2 = 82 + 62
PR2 = 64 + 36
PR2 = 100
∴ PR = `sqrt100` = 10 cm
APPEARS IN
RELATED QUESTIONS
ABCD is a rectangle whose three vertices are B (4, 0), C(4, 3) and D(0,3). The length of one of its diagonals is
(A) 5
(B) 4
(C) 3
(D) 25
Prove that the points A(0, −1), B(−2, 3), C(6, 7) and D(8, 3) are the vertices of a rectangle ABCD?
Identify, with reason, if the following is a Pythagorean triplet.
(3, 5, 4)
In ∆ABC, ∠BAC = 90°, seg BL and seg CM are medians of ∆ABC. Then prove that:
4(BL2 + CM2) = 5 BC2
Triangle PQR is right-angled at vertex R. Calculate the length of PR, if: PQ = 34 cm and QR = 33.6 cm.
Find the Pythagorean triplet from among the following set of numbers.
2, 6, 7
In a triangle ABC right angled at C, P and Q are points of sides CA and CB respectively, which divide these sides the ratio 2 : 1.
Prove that : 9(AQ2 + BP2) = 13AB2
An isosceles triangle has equal sides each 13 cm and a base 24 cm in length. Find its height
In an equilateral triangle PQR, prove that PS2 = 3(QS)2.
Two squares having same perimeter are congruent.
