Advertisements
Advertisements
Question
In triangle PQR, angle Q = 90°, find: PR, if PQ = 8 cm and QR = 6 cm
Advertisements
Solution
Given:
PQ = 8 cm
QR = 6 cm
PR =?
∠PQR = 90°
According to Pythagoras Theorem,
(PR)2 = (PQ)2 + (QR)2
PR2 = 82 + 62
PR2 = 64 + 36
PR2 = 100
∴ PR = `sqrt100` = 10 cm
APPEARS IN
RELATED QUESTIONS
A ladder leaning against a wall makes an angle of 60° with the horizontal. If the foot of the ladder is 2.5 m away from the wall, find the length of the ladder
A man goes 10 m due east and then 24 m due north. Find the distance from the starting point
Which of the following can be the sides of a right triangle?
2.5 cm, 6.5 cm, 6 cm
In the case of right-angled triangles, identify the right angles.
The perimeter of a triangle with vertices (0, 4), (0, 0) and (3, 0) is
(A)\[7 + \sqrt{5}\]
(B) 5
(C) 10
(D) 12
AD is drawn perpendicular to base BC of an equilateral triangle ABC. Given BC = 10 cm, find the length of AD, correct to 1 place of decimal.
Find the Pythagorean triplet from among the following set of numbers.
2, 6, 7
Find the length of the perpendicular of a triangle whose base is 5cm and the hypotenuse is 13cm. Also, find its area.
From the given figure, in ∆ABQ, if AQ = 8 cm, then AB =?
Prove that the area of the semicircle drawn on the hypotenuse of a right angled triangle is equal to the sum of the areas of the semicircles drawn on the other two sides of the triangle.
In an isosceles triangle PQR, the length of equal sides PQ and PR is 13 cm and base QR is 10 cm. Find the length of perpendicular bisector drawn from vertex P to side QR.
