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Question
The foot of a ladder is 6 m away from its wall and its top reaches a window 8 m above the ground. Find the length of the ladder.
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Solution
Let the length of the ladder be x m.
In right angled ΔABC,
AC2 = AB2 + BC2 ...[By Pythagoras theorem]
⇒ (x)2 = (8)2 + (6)2
⇒ `sqrt((8)^2 + (6)^2)` = `sqrt(64 + 36)` = `sqrt(100)`
⇒ x = 10 m
Hence, the length of the ladder is 10 m.
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