Advertisements
Advertisements
प्रश्न
The foot of a ladder is 6 m away from its wall and its top reaches a window 8 m above the ground. Find the length of the ladder.
Advertisements
उत्तर
Let the length of the ladder be x m.

In right angled ΔABC,
AC2 = AB2 + BC2 ...[By Pythagoras theorem]
⇒ (x)2 = (8)2 + (6)2
⇒ `sqrt((8)^2 + (6)^2)` = `sqrt(64 + 36)` = `sqrt(100)`
⇒ x = 10 m
Hence, the length of the ladder is 10 m.
APPEARS IN
संबंधित प्रश्न
Sides of triangle are given below. Determine it is a right triangle or not? In case of a right triangle, write the length of its hypotenuse. 13 cm, 12 cm, 5 cm
Find the length diagonal of a rectangle whose length is 35 cm and breadth is 12 cm.
In an isosceles triangle, length of the congruent sides is 13 cm and its base is 10 cm. Find the distance between the vertex opposite the base and the centroid.
Prove that in a right angle triangle, the square of the hypotenuse is equal to the sum of squares of the other two sides.
Find the length of the hypotenuse of a triangle whose other two sides are 24cm and 7cm.
The foot of a ladder is 6m away from a wall and its top reaches a window 8m above the ground. If the ladder is shifted in such a way that its foot is 8m away from the wall to what height does its tip reach?
In a triangle ABC, AC > AB, D is the midpoint BC, and AE ⊥ BC. Prove that: AB2 + AC2 = 2AD2 + `(1)/(2)"BC"^2`
In triangle ABC, line I, is a perpendicular bisector of BC.
If BC = 12 cm, SM = 8 cm, find CS
In a quadrilateral ABCD, ∠A + ∠D = 90°. Prove that AC2 + BD2 = AD2 + BC2
[Hint: Produce AB and DC to meet at E.]
Prove that the area of the semicircle drawn on the hypotenuse of a right angled triangle is equal to the sum of the areas of the semicircles drawn on the other two sides of the triangle.
