Advertisements
Advertisements
प्रश्न
The foot of a ladder is 6 m away from its wall and its top reaches a window 8 m above the ground. If the ladder is shifted in such a way that its foot is 8 m away from the wall, to what height does its top reach?
Advertisements
उत्तर
Let the height of the top be x m.

In right angled ΔACB,
AC2 = AB2 + BC2 ...[By Pythagoras theorem]
⇒ AB2 = AC2 – BC2
⇒ x2 = (10)2 – (8)2 = 100 – 64
⇒ x = `sqrt(36)`
⇒ x = 6 m
Hence, the height of the top is 6 m.
APPEARS IN
संबंधित प्रश्न
If the sides of a triangle are 6 cm, 8 cm and 10 cm, respectively, then determine whether the triangle is a right angle triangle or not.
ABCD is a rhombus. Prove that AB2 + BC2 + CD2 + DA2= AC2 + BD2
D and E are points on the sides CA and CB respectively of a triangle ABC right angled at C. Prove that AE2 + BD2 = AB2 + DE2
In a trapezium ABCD, seg AB || seg DC seg BD ⊥ seg AD, seg AC ⊥ seg BC, If AD = 15, BC = 15 and AB = 25. Find A(▢ABCD)

In a rectangle ABCD,
prove that: AC2 + BD2 = AB2 + BC2 + CD2 + DA2.
If P and Q are the points on side CA and CB respectively of ΔABC, right angled at C, prove that (AQ2 + BP2) = (AB2 + PQ2)
A ladder 25m long reaches a window of a building 20m above the ground. Determine the distance of the foot of the ladder from the building.
From a point O in the interior of aΔABC, perpendicular OD, OE and OF are drawn to the sides BC, CA and AB respectively. Prove that: AF2 + BD2 + CE2 = OA2 + OB2 + OC2 - OD2 - OE2 - OF2
Lengths of sides of a triangle are 3 cm, 4 cm and 5 cm. The triangle is ______.
In a triangle, sum of squares of two sides is equal to the square of the third side.
