Advertisements
Advertisements
प्रश्न
The foot of a ladder is 6 m away from its wall and its top reaches a window 8 m above the ground. If the ladder is shifted in such a way that its foot is 8 m away from the wall, to what height does its top reach?
Advertisements
उत्तर
Let the height of the top be x m.
In right angled ΔACB,
AC2 = AB2 + BC2 ...[By Pythagoras theorem]
⇒ AB2 = AC2 – BC2
⇒ x2 = (10)2 – (8)2 = 100 – 64
⇒ x = `sqrt(36)`
⇒ x = 6 m
Hence, the height of the top is 6 m.
APPEARS IN
संबंधित प्रश्न
ABC is a triangle right angled at C. If AB = 25 cm and AC = 7 cm, find BC.
Find the perimeter of the rectangle whose length is 40 cm and a diagonal is 41 cm.
In triangle ABC, given below, AB = 8 cm, BC = 6 cm and AC = 3 cm. Calculate the length of OC.
In equilateral Δ ABC, AD ⊥ BC and BC = x cm. Find, in terms of x, the length of AD.
The sides of a certain triangle is given below. Find, which of them is right-triangle
6 m, 9 m, and 13 m
In the given figure, AD is a median of a triangle ABC and AM ⊥ BC. Prove that:
(i) `"AC"^2 = "AD"^2 + "BC"."DM" + (("BC")/2)^2`
(ii) `"AB"^2 = "AD"^2 - "BC"."DM" + (("BC")/2)^2`
(iii) `"AC"^2 + "AB"^2 = 2"AD"^2 + 1/2"BC"^2`
The longest side of a right angled triangle is called its ______.
Two angles are said to be ______, if they have equal measures.
If the areas of two circles are the same, they are congruent.
Height of a pole is 8 m. Find the length of rope tied with its top from a point on the ground at a distance of 6 m from its bottom.
