Advertisements
Advertisements
Question
The foot of a ladder is 6 m away from its wall and its top reaches a window 8 m above the ground. If the ladder is shifted in such a way that its foot is 8 m away from the wall, to what height does its top reach?
Advertisements
Solution
Let the height of the top be x m.
In right angled ΔACB,
AC2 = AB2 + BC2 ...[By Pythagoras theorem]
⇒ AB2 = AC2 – BC2
⇒ x2 = (10)2 – (8)2 = 100 – 64
⇒ x = `sqrt(36)`
⇒ x = 6 m
Hence, the height of the top is 6 m.
APPEARS IN
RELATED QUESTIONS
In Fig., ∆ABC is an obtuse triangle, obtuse angled at B. If AD ⊥ CB, prove that AC2 = AB2 + BC2 + 2BC × BD
In Figure ABD is a triangle right angled at A and AC ⊥ BD. Show that AC2 = BC × DC
Prove that, in a right-angled triangle, the square of the hypotenuse is equal to the sum of the square of remaining two sides.
In ∆ABC, ∠BAC = 90°, seg BL and seg CM are medians of ∆ABC. Then prove that:
4(BL2 + CM2) = 5 BC2
Prove that (1 + cot A - cosec A ) (1 + tan A + sec A) = 2
Find the Pythagorean triplet from among the following set of numbers.
4, 5, 6
The sides of the triangle are given below. Find out which one is the right-angled triangle?
1.5, 1.6, 1.7
Find the length of the support cable required to support the tower with the floor
A flag pole 18 m high casts a shadow 9.6 m long. Find the distance of the top of the pole from the far end of the shadow.
In a right-angled triangle ABC, if angle B = 90°, then which of the following is true?
