Advertisements
Advertisements
प्रश्न
Two poles of 10 m and 15 m stand upright on a plane ground. If the distance between the tops is 13 m, find the distance between their feet.
Advertisements
उत्तर
Let BC = x m
In right-angled ΔACB,
AB2 = AC2 + BC2 ...[By Pythagoras theorem]
⇒ (13)2 = (5)2 + x2
⇒ 169 – 25 = x2
⇒ 144 = x2
⇒ x = `sqrt(144)`
⇒ x = 12 m
Hence, the distance between the feet of two poles is 12 m.
APPEARS IN
संबंधित प्रश्न
ABCD is a rectangle whose three vertices are B (4, 0), C(4, 3) and D(0,3). The length of one of its diagonals is
(A) 5
(B) 4
(C) 3
(D) 25
A ladder leaning against a wall makes an angle of 60° with the horizontal. If the foot of the ladder is 2.5 m away from the wall, find the length of the ladder
In a right triangle ABC right-angled at C, P and Q are the points on the sides CA and CB respectively, which divide these sides in the ratio 2 : 1. Prove that
`(i) 9 AQ^2 = 9 AC^2 + 4 BC^2`
`(ii) 9 BP^2 = 9 BC^2 + 4 AC^2`
`(iii) 9 (AQ^2 + BP^2 ) = 13 AB^2`
Prove that, in a right-angled triangle, the square of the hypotenuse is equal to the sum of the square of remaining two sides.
Identify, with reason, if the following is a Pythagorean triplet.
(3, 5, 4)
Find the length of the hypotenuse of a triangle whose other two sides are 24cm and 7cm.
In a triangle ABC, AC > AB, D is the midpoint BC, and AE ⊥ BC. Prove that: AC2 - AB2 = 2BC x ED
An isosceles triangle has equal sides each 13 cm and a base 24 cm in length. Find its height
From the given figure, in ∆ABQ, if AQ = 8 cm, then AB = ?
Jayanti takes shortest route to her home by walking diagonally across a rectangular park. The park measures 60 metres × 80 metres. How much shorter is the route across the park than the route around its edges?
