Advertisements
Advertisements
प्रश्न
Triangle PQR is right-angled at vertex R. Calculate the length of PR, if: PQ = 34 cm and QR = 33.6 cm.
Advertisements
उत्तर
Given: ∆PQR right angled at R and PQ = 34 cm, QR = 33.6 cm.
To find: Length of PR.
According to Pythagoras' Theorem,
PR2 + QR2 = PQ2
PR2 + 33.62 = 342
PR2+ 1128.96= 1156
PR2 = 1156 − 1128.96
PR = `sqrt27.04`
∴ PR = 5.2 cm
APPEARS IN
संबंधित प्रश्न
ABC is a right triangle right-angled at C. Let BC = a, CA = b, AB = c and let p be the length of perpendicular from C on AB, prove that
(i) cp = ab
`(ii) 1/p^2=1/a^2+1/b^2`
PQR is a triangle right angled at P. If PQ = 10 cm and PR = 24 cm, find QR.
Find the perimeter of the rectangle whose length is 40 cm and a diagonal is 41 cm.
In the given figure, ∠DFE = 90°, FG ⊥ ED, If GD = 8, FG = 12, find (1) EG (2) FD and (3) EF
In the given figure, ∠B = 90°, XY || BC, AB = 12 cm, AY = 8cm and AX : XB = 1 : 2 = AY : YC.
Find the lengths of AC and BC.
Find the value of (sin2 33 + sin2 57°)
In the figure, find AR
In ∆PQR, PD ⊥ QR such that D lies on QR. If PQ = a, PR = b, QD = c and DR = d, prove that (a + b)(a – b) = (c + d)(c – d).
Two poles of 10 m and 15 m stand upright on a plane ground. If the distance between the tops is 13 m, find the distance between their feet.
The foot of a ladder is 6 m away from its wall and its top reaches a window 8 m above the ground. If the ladder is shifted in such a way that its foot is 8 m away from the wall, to what height does its top reach?
