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प्रश्न
In figure AB = BC and AD is perpendicular to CD.
Prove that: AC2 = 2BC. DC.
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उत्तर
Pythagoras theorem states that in a right-angled triangle, the square on the hypotenuse is equal to the sum of the squares on the remaining two sides.
We consider the ΔACD and applying Pythagoras theorem we get,
AC2 = AD2 + DC2
= ( AB2 - DB2 ) + ( DB + BC )2
= BC2 - DB2 + DB2 + BC2 + 2DB.BC ...( Given, AB = BC )
= 2BC2 + 2DB.BC
= 2BC( BC + DB )
= 2BC . DC
Hence proved.
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