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Question
Two poles of 10 m and 15 m stand upright on a plane ground. If the distance between the tops is 13 m, find the distance between their feet.
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Solution
Let BC = x m
In right-angled ΔACB,
AB2 = AC2 + BC2 ...[By Pythagoras theorem]
⇒ (13)2 = (5)2 + x2
⇒ 169 – 25 = x2
⇒ 144 = x2
⇒ x = `sqrt(144)`
⇒ x = 12 m
Hence, the distance between the feet of two poles is 12 m.
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