Advertisements
Advertisements
Question
In the figure, find AR
Advertisements
Solution
∆AFI, ∆FRI are right triangles.
By Pythagoras theorem,
AF2 = AI2 – FI2
= 252 – 152
= 625 – 225
= 400
= 202
∴ AF = 20 feet.
FR2 = RI2 – FI2
= 172 – 152
= 289 – 225
= 64
= 82
FR = 8 feet.
∴ AR = AF + FR
= 20 + 8
= 28 feet.
APPEARS IN
RELATED QUESTIONS
If ABC is an equilateral triangle of side a, prove that its altitude = ` \frac { \sqrt { 3 } }{ 2 } a`
Sides of triangle are given below. Determine it is a right triangle or not? In case of a right triangle, write the length of its hypotenuse. 50 cm, 80 cm, 100 cm
The perpendicular from A on side BC of a Δ ABC intersects BC at D such that DB = 3CD . Prove that 2AB2 = 2AC2 + BC2.

Identify, with reason, if the following is a Pythagorean triplet.
(5, 12, 13)
In ∆ABC, ∠BAC = 90°, seg BL and seg CM are medians of ∆ABC. Then prove that:
4(BL2 + CM2) = 5 BC2

In triangle ABC, AB = AC and BD is perpendicular to AC.
Prove that: BD2 − CD2 = 2CD × AD
In an isosceles triangle ABC; AB = AC and D is the point on BC produced.
Prove that: AD2 = AC2 + BD.CD.
Find the unknown side in the following triangles
An isosceles triangle has equal sides each 13 cm and a base 24 cm in length. Find its height
Two circles having same circumference are congruent.
