Advertisements
Advertisements
प्रश्न
In the figure, find AR
Advertisements
उत्तर
∆AFI, ∆FRI are right triangles.
By Pythagoras theorem,
AF2 = AI2 – FI2
= 252 – 152
= 625 – 225
= 400
= 202
∴ AF = 20 feet.
FR2 = RI2 – FI2
= 172 – 152
= 289 – 225
= 64
= 82
FR = 8 feet.
∴ AR = AF + FR
= 20 + 8
= 28 feet.
APPEARS IN
संबंधित प्रश्न
PQR is a triangle right angled at P and M is a point on QR such that PM ⊥ QR. Show that PM2 = QM . MR
A ladder 10 m long reaches a window 8 m above the ground. Find the distance of the foot of the ladder from base of the wall.
In ∆ABC, ∠BAC = 90°, seg BL and seg CM are medians of ∆ABC. Then prove that:
4(BL2 + CM2) = 5 BC2
In the given figure, ∠B = 90°, XY || BC, AB = 12 cm, AY = 8cm and AX : XB = 1 : 2 = AY : YC.
Find the lengths of AC and BC.
Diagonals of rhombus ABCD intersect each other at point O.
Prove that: OA2 + OC2 = 2AD2 - `"BD"^2/2`
In the figure below, find the value of 'x'.
Find the Pythagorean triplet from among the following set of numbers.
4, 7, 8
In a right-angled triangle ABC,ABC = 90°, AC = 10 cm, BC = 6 cm and BC produced to D such CD = 9 cm. Find the length of AD.
Rithika buys an LED TV which has a 25 inches screen. If its height is 7 inches, how wide is the screen? Her TV cabinet is 20 inches wide. Will the TV fit into the cabinet? Give reason
In an equilateral triangle PQR, prove that PS2 = 3(QS)2.
