Advertisements
Advertisements
प्रश्न
In the figure, find AR
Advertisements
उत्तर
∆AFI, ∆FRI are right triangles.
By Pythagoras theorem,
AF2 = AI2 – FI2
= 252 – 152
= 625 – 225
= 400
= 202
∴ AF = 20 feet.
FR2 = RI2 – FI2
= 172 – 152
= 289 – 225
= 64
= 82
FR = 8 feet.
∴ AR = AF + FR
= 20 + 8
= 28 feet.
APPEARS IN
संबंधित प्रश्न
Prove that the diagonals of a rectangle ABCD, with vertices A(2, -1), B(5, -1), C(5, 6) and D(2, 6), are equal and bisect each other.
Two poles of heights 6 m and 11 m stand on a plane ground. If the distance between the feet of the poles is 12 m, find the distance between their tops.
Identify, with reason, if the following is a Pythagorean triplet.
(5, 12, 13)
Find the side and perimeter of a square whose diagonal is 10 cm.
If the sides of the triangle are in the ratio 1: `sqrt2`: 1, show that is a right-angled triangle.
If in a ΔPQR, PR2 = PQ2 + QR2, then the right angle of ∆PQR is at the vertex ________
If ‘l‘ and ‘m’ are the legs and ‘n’ is the hypotenuse of a right angled triangle then, l2 = ________
In a right angled triangle, if length of hypotenuse is 25 cm and height is 7 cm, then what is the length of its base?
In a right-angled triangle ABC, if angle B = 90°, BC = 3 cm and AC = 5 cm, then the length of side AB is ______.
In a right-angled triangle ABC, if angle B = 90°, then which of the following is true?
