Advertisements
Advertisements
Question
Triangle ABC is right-angled at vertex A. Calculate the length of BC, if AB = 18 cm and AC = 24 cm.
Advertisements
Solution
Given: ∆ ABC right angled at A and AB = 18 cm, AC = 24 cm.

To find: Length of BC.
According to Pythagoras Theorem,
BC2 = AB2 + AC2
= 182 + 242 = 324 + 576 = 900
∴ BC =`sqrt900=sqrt(30xx30)` = 30 cm
APPEARS IN
RELATED QUESTIONS
ABC is a right triangle right-angled at C. Let BC = a, CA = b, AB = c and let p be the length of perpendicular from C on AB, prove that
(i) cp = ab
`(ii) 1/p^2=1/a^2+1/b^2`
Walls of two buildings on either side of a street are parallel to each other. A ladder 5.8 m long is placed on the street such that its top just reaches the window of a building at the height of 4 m. On turning the ladder over to the other side of the street, its top touches the window of the other building at a height 4.2 m. Find the width of the street.
The given figure shows a quadrilateral ABCD in which AD = 13 cm, DC = 12 cm, BC = 3 cm and ∠ABD = ∠BCD = 90o. Calculate the length of AB.
If the sides of the triangle are in the ratio 1: `sqrt2`: 1, show that is a right-angled triangle.
Prove that `(sin θ + cosec θ)^2 + (cos θ + sec θ)^2 = 7 + tan^2 θ + cot^2 θ`.
Prove that in a right angle triangle, the square of the hypotenuse is equal to the sum of squares of the other two sides.
In triangle PQR, angle Q = 90°, find: PR, if PQ = 8 cm and QR = 6 cm
An isosceles triangle has equal sides each 13 cm and a base 24 cm in length. Find its height
The top of a broken tree touches the ground at a distance of 12 m from its base. If the tree is broken at a height of 5 m from the ground then the actual height of the tree is ______.
The foot of a ladder is 6 m away from its wall and its top reaches a window 8 m above the ground. If the ladder is shifted in such a way that its foot is 8 m away from the wall, to what height does its top reach?
