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Question
The marks out of 100 obtained by Kunal and Soni in the Half Yearly Examination are given below:
| Subjects | English | Hindi | Maths | Science | S. Science | Sanskirt |
| Kunal | 72 | 81 | 92 | 96 | 64 | 85 |
| Soni | 86 | 89 | 90 | 82 | 75 | 82 |
- Draw a double bar graph by choosing appropriate scale.
- Calculate the total percentage of marks obtained by Soni.
- Calculate the total percentage of marks obtained by Kunal.
- Compare the percentages of marks obtained by Kunal and Soni.
- In how many subjects did Soni get more marks than Kunal? Which are those subjects?
- Who got more marks in S. Science and what was the difference of marks?
- In which subject the difference of marks was maximum and by how much?
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Solution
a. Steps to construct the bar graphs are as follows:
Step I: We draw two lines perpendicular to each other on a graph paper and call them horizontal and vertical axes.
Step II: Along the horizontal axis, OX mark the subjects and along vertical axis, OY mark the marks obtained.
Step III: We choose a suitable scale to determine the heights of bars. Here, we choose the scale as 1 small division to represent 5 marks.
Step IV: First, we draw the bars for Kunal and then bars for Soni for different years.
Bars for Kunal and Soni shaded separately and the shading is shown in the top right corner of the graph paper.
b. Total percentage of marks obtained by Soni
= `("Total marks obtained by Soni in six subjects"/600 xx 100)%`
= `((86 + 89 + 90 + 82 + 75 + 82)/600 xx 100)%`
= `(504/600 xx 100)%`
= 84%
c. Total percentage of marks obtained by Kunal
= `("Total marks obtained by Kunal in six subjects"/600 xx 100)%`
= `((72 + 81 + 92 + 96 + 64 + 85)/600 xx 100)%`
= `(490/600 xx 100)%`
= 81.6%
d. Ratio of percentage marks obtained by Kunal and Soni = 81.6 : 84 = 34 : 35
e. In English, Hindi and S.Science, Soni get more marks than Kunal.
f. Marks obtained by Kunal and Soni is S.Science are 64 and 75, respectively. Therefore, Soni got more marks than Kunal by 11 marks.
g. In English and Science, the difference of marks was maximum = (504 – 490), i.e. 14 marks.
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