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Question
The decomposition of hydrocarbon follows the equation
k = `(4.5 xx 10^11 s^-1) e^(-28000 K//T)`
Calculate Ea.
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Solution
According to the Arrhenius equation, k = `Ae^((-E_a)/(RT))`
∴ `-E_a/(RT) = -(28000 K)/T`
Ea = 28000 K × R
= 28000 K × 8.314 JK−1 mol−1
= 232.79 kJ mol−1
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