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The 4th Term of an A.P. is Three Times the First and the 7th Term Exceeds Twice the Third Term by 1. Find the First Term and the Common Difference.

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Question

The 4th term of an A.P. is three times the first and the 7th term exceeds twice the third term by 1. Find the first term and the common difference.

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Solution

Given:
Let the first term of the A.P. be a and the common difference be d.

\[a_4 = 3a\]

\[ \Rightarrow a + \left( 4 - 1 \right)d = 3a\]

\[ \Rightarrow a + 3d = 3a\]

\[ \Rightarrow 3d = 2a\]

\[ \Rightarrow a = \frac{3d}{2} . . . (i)\]

\[\text { And,} a_7 - 2 a_3 = 1\]

\[ \Rightarrow a + \left( 7 - 1 \right)d - 2\left[ a + \left( 3 - 1 \right)d \right] = 1\]

\[ \Rightarrow a + 6d - 2(a + 2d) = 1\]

\[ \Rightarrow a + 6d - 2a - 4d = 1\]

\[ \Rightarrow - a + 2d = 1\]

\[ \Rightarrow - \frac{3d}{2} + 2d = 1 \left[ \text { From } (i) \right] \]

\[ \Rightarrow \frac{- 3d + 4d}{2} = 1\]

\[ \Rightarrow \frac{d}{2} = 1\]

\[ \Rightarrow d = 2\]

\[\text { Putting the value in (i), we get }: \]

\[a = \frac{3 \times 2}{2}\]

\[ \Rightarrow a = 3\]

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Chapter 19: Arithmetic Progression - Exercise 19.2 [Page 12]

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R.D. Sharma Mathematics [English] Class 11
Chapter 19 Arithmetic Progression
Exercise 19.2 | Q 16 | Page 12

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