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If the Sum of Three Numbers in A.P. is 24 and Their Product is 440, Find the Numbers.

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Question

If the sum of three numbers in A.P. is 24 and their product is 440, find the numbers.

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Solution

\[\text { Let the three numbers be } (a - d), a, (a + d) . \]

\[\text { Sum } = 24\]

\[ \Rightarrow (a - d) + a + (a + d) = 24\]

\[ \Rightarrow 3a = 24\]

\[ \Rightarrow a = 8 . . . (i)\]

\[\text { Product } = a(a - d)(a + d) = 440\]

\[ \Rightarrow a( a^2 - d^2 ) = 440\]

\[ \Rightarrow 8(64 - d^2 ) = 440 \left(\text {  Form } (i) \right)\]

\[ \Rightarrow (64 - d^2 ) = 55\]

\[ \Rightarrow d^2 = 9\]

\[ \Rightarrow d = \pm 3\]

\[\text { With a = 8, d = 3, we have }: \]

\[5, 8, 11\]

\[\text { With a = 8, d = - 3, we have: } \]

\[11, 8, 5\]

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Chapter 19: Arithmetic Progression - Exercise 19.2 [Page 15]

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R.D. Sharma Mathematics [English] Class 11
Chapter 19 Arithmetic Progression
Exercise 19.2 | Q 5 | Page 15

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