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Find the Sum of the Following Arithmetic Progression : 50, 46, 42, ... to 10 Terms

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Question

Find the sum of the following arithmetic progression :

50, 46, 42, ... to 10 terms

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Solution

50, 46, 42 ... to 10 terms

\[\text { We have }: \]

\[ a = 50, d = \left( 46 - 50 \right) = - 4\]

\[n = 10\]

\[ S_n = \frac{n}{2}\left[ 2a + (n - 1)d \right]\]

\[ = \frac{10}{2}\left[ 2 \times 50 + (10 - 1)( - 4) \right]\]

\[ = 5\left[ 100 - 36 \right] = 320\]

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Chapter 19: Arithmetic Progression - Exercise 19.4 [Page 30]

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R.D. Sharma Mathematics [English] Class 11
Chapter 19 Arithmetic Progression
Exercise 19.4 | Q 1.1 | Page 30

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