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Question
Find the 12th term from the following arithmetic progression:
1, 4, 7, 10, ..., 88
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Solution
1, 4, 7, 10...88
Consider the given progression with 88 as the first term and −3 as the common difference.
12th term from the end = \[88 + (12 - 1)( - 3) = 55\]
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